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3 years ago

Please help!Which organisms are secondary consumers? Check all that apply.

Chemistry

2 answers:

Artemon [7]3 years ago

5 0

Answer:

It's a sea otter and horn shark.

Explanation:

I just answered it

Alla [95]3 years ago

4 0

Answer:Sea Otter and hark

Explanation:

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A match burns because of what type(s) of properties?

GalinKa [24]

It would be a chemical property

4 0

4 years ago

Read 2 more answers

Convert 9.32x 10 23ª atoms of au to moles of au

7nadin3 [17]

Answer:

$\huge\boxed{\sf no.\ of\ moles = 1.55\ moles }$

Explanation:

Given:

Number of atoms = $9.32 \times 10^{23}$ atoms

Avogadro's Number = $6.023 \times 10^{23}$ atom / mol

Required:

Moles = ?

Formula:

$\displaystyle No.\ of\ moles = \frac{no. \ of \ atoms }{avogadro's \ no.}$

Solution:

$\displaystyle no. \ of \ moles = \frac{9.32\times 10^{23}}{6.023 \times 10^{23}}$

no. of moles = 1.55 moles

$\rule[225]{225}{2}$

Hope this helped!

5 0

3 years ago

Jan Baptista van Helmont did an important experiment related to photosynthesis. He weighed a small willow tree and a pot of soil

Georgia [21]

Answer:

Explanation:

This experiment demonstrate that a plant don't need only water to grow and increase its mass.

A plant will also need nutrients located in the soil that will help it grow and increase its mass.

8 0

3 years ago

In the reaction 2SO2(g) + O2(g) -> 2SO3(g) how many liters of oxygen are needed produced 4 liters of SO3 at STP?

Sophie [7]

Answer:

2 litres

Explanation:

find the details in the attached picture.

7 0

4 years ago

Quinine in a 1.664-g antimalarial tablet was dissolved in sufficient 0.10 M HCl to give 500 mL of solution. A 15.00-mL aliquot w

Karo-lina-s [1.5K]

Answer:

533.33 mg quinine

Explanation:

First we calculate the concentration of the diluted sample, using the values obtained by the standard:

288 * 100 ppm / 180 = 160 ppm

Now we use the dilution factors to calculate the concentration of quinine in the original sample:

160 ppm * 100mL/15mL = 1066.67 ppm

ppm can be defined as mg of quinine/L solvent:

500 mL solution ⇒ 500/1000 = 0.5 L

1066.67 ppm * 0.5L = 533.33 mg quinine

4 0

3 years ago