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Sliva [168]
3 years ago
7

Explain why magnesium and aluminium react in a similar way?

Chemistry
1 answer:
postnew [5]3 years ago
3 0
Because magnesium loses its electrons easily than aluminum
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You open the fridge and the milk is sour (spoiled). What has
Sloan [31]
Pretty sure it’s a chemical change.
6 0
3 years ago
Read 2 more answers
What is the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis according to the balanced equation:
Zinaida [17]

Taking into account the reaction stoichiometry, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 H₂O → 2 H₂ + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • H₂O: 2 moles
  • H₂: 2 moles
  • O₂: 1 mole

The molar mass of the compounds is:

  • H₂O: 18 g/mole
  • H₂: 2 g/mole
  • O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • H₂O: 2 moles ×18 g/mole= 36 grams
  • H₂: 2 moles ×2 g/mole= 4 grams
  • O₂: 1 mole ×32 g/mole= 32 grams

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theorical yield of O₂</h3>

The following rule of three can be applied: if by reaction stoichiometry 36 grams of water form 32 grams of oxygen, 29.2 grams of water form how much mass of oxygen?

mass of oxygen=\frac{29.2 grams of waterx32 grams of oxygen}{36 grams of water}

<u><em>mass of oxygen= 25.956 grams</em></u>

Finally, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
1 year ago
How many moles of CO2 are there in 8.91 x 1023 molecules of CO2?<br> (1 mole= 6.02 x 1023)
Karo-lina-s [1.5K]

Answer:

<h2>1.48 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.91 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{8.91}{6.02}  \\  = 1.480066...

We have the final answer as

<h3>1.48 moles</h3>

Hope this helps you

6 0
3 years ago
A 28.4 g sample of an unknown metal is heated to 39.4 °C, then is placed in a calorimeter containing 50.0 g of water. Temperatur
Alisiya [41]

Answer:

THE SPECIFIC HEAT OF THE METAL IS 0.8983 J/g °C

Explanation:

In solving the problem, we have to understand that:

Heat lost by the metal = Heat gained by the water in the bomb calorimeter

First is to calculate the heat evolved from the reaction

Heat = mass * specific heat * change in temperature

Mass of water = 50 g

specific heat of water = 4.184 J/g °C

Change in temperature = 23 - 21 = 2 °C

So therefore,

Heat = 50 * 4.184 * 2

Heat = 418.4 J

Next is to solve for the specific heat of the metal;

Heat lost by the metal is the same as the heat gained by water

Heat = mass * specific heat of  metal * change in temperature

Change in temperature = 39.4 °C - 23 °C = 16.4 °C

418.4 = 28.4 * C * 16.4

C = 418.4 / 28.4 * 16.4

C = 418.4 / 465.76

C = 0.8983 J/ g °C

The specific heat of the metal is hence 0.8983 J/g °C

3 0
3 years ago
What is the density of a piece of metal that has a mass of 75.8g and a volume of 7.09
Mice21 [21]

Answer:

10.69g/cm^3 or 0.0106kg/m^3

Explanation:

10.69 g/cm^3: I wrote this answer because your question doesn't mention whether volume is in cm^3 or m^3. If its in cm^3, then this is your answer.

0.0106kg/m^3: This might also be the answer if the volume is in m^3. If it is in m^3 then you have convert grams into kilograms.

So technically since you questions incomplete, the equation for measuring density is P= m/v

P= rho (density)

m= mass

v= volume

Hope it helps- Z

3 0
2 years ago
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