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12345 [234]
3 years ago
5

Please help and explain how to do it if you can :)

Mathematics
1 answer:
never [62]3 years ago
3 0

Answer:

Graph C.

Step-by-step explanation:

If you calculate f for x=0, you get f(0)=3*1=3. This rules out answer A already.

Next, you can expect the graph to approach y=0 for large x. The larger the x, the more times you're multiplying by 0.5. Graph C is the only one that does that. So even without actually graphing it, you know that C is the one.

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If the equation y=-5x+12 is translated up five units, what would the new equation be?
Maurinko [17]

Answer:

y=-5x+17

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
CAN SOMEBODY HELP PLS
Sophie [7]

\frac{9}{ - j}

5 0
2 years ago
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A sum of $9, 000 paid into a bank account for two months (61 days) to attract simple interest will produce $9, 020 at the and of
Juliette [100K]

Answer:

Rate of interest will be 1.33 %

Return on this investment = =\frac{9020-9000}{9000}=0.222 %

Step-by-step explanation:

We have given principle amount P = $9000

Time = 61 days = \frac{61}{365}=0.167\ years

We have to find the rate of interest

Total amount produce at the end of term = $9020

So interest = $9020 - $9000 = $20

We know that simple interest =\frac{principle\ amount\times rate\times\ time}{100}

20=\frac{9000\times rate\times\\ 0.167}{100}

rate=1.33 %

Return on this investment = =\frac{9020-9000}{9000}=0.222 %

6 0
4 years ago
HELP PLSSSSSSSSSS ASAP
seropon [69]

Answer:

1. 4 gal= 16 qt.

2. 6 qt= 12 pt.

3. 11 pt= 176 fl oz.

4. 18 c= 144 fl oz.

5. 48 qt= 12 gal.

6. 17 gal= 136 pt.

7. 19 qt= 76 c.

8. 256 c= 16 gal.

9. 12 gal= 96 pt.

10. 28 c= 14 pt.

11. 17 c= 136 fl oz.

12. 128 fl oz= 16 c.

13. 8 gal= 32 qt.

14. 20 qt= 640 fl oz.

15. 4 qt= 8 pt.

16. 18 qt= 72 c.

+ if this helped you, please consider marking it the Brainliest.

8 0
3 years ago
How much money would you have in your savings balance after 3 years if you initially invested $900 and had an interest rate of 1
denis-greek [22]

assuming simple interest

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$900\\ r=rate\to 1\%\to \frac{1}{100}\dotfill &0.01\\ t=years\dotfill &3 \end{cases} \\\\\\ A=900[1+(0.01)(3)]\implies A=900(1.03)\implies A=927

8 0
2 years ago
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