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Maurinko [17]
3 years ago
6

A rectangular deck

Mathematics
2 answers:
nalin [4]3 years ago
8 0
Original length: 14 ft. New length x + 14.
Original width: 12 ft. New width x + 12.

New area:

A = LW  or LW = A

(x + 14)(x + 12) = 280

x^2 + 14x + 12x + 168 = 280

x^2 + 26x - 112 = 0

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-26 \pm \sqrt{26^2 - 4(1)(-112)}}{2(1)}

x = \dfrac{-26 \pm \sqrt{676 + 448}}{2}

x = \dfrac{-26 \pm \sqrt{1124}}{2}

x = \dfrac{-26 \pm 2\sqrt{281}}{2}

x = -13 \pm \sqrt{281}

x \approx -29.76   or   x \approx 3.76

We discard the negative answer.

Answer:

Exact:
(-13 + \sqrt{281})~ ft

Approximate:
3.76 ~ft
denpristay [2]3 years ago
4 0
Both dimensions were increased by 127.

The other response seems more complex so probably ignore mine. I probably misinterpreted the question.

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