<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
Answer:
In this equation n = 15
Step-by-step explanation:
In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.
3^5 * 9^5 = 3^n
3^5 * (3^2)^5 = 3^n
3^5 * 3^10 = 3^n
3^15 = 3^n
Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n
Answer:
X = 2 or X = -10
Step-by-step explanation:
We know either3x+12=18or3x+12=−18
3x+12=18(Possibility 1)
3x+12−12=18−12(Subtract 12 from both sides)
3x=6
3x
3
=
6
3
(Divide both sides by 3)
x=2
3x+12=−18(Possibility 2)
3x+12−12=−18−12(Subtract 12 from both sides)
3x=−30
3x
3
=
−30
3
(Divide both sides by 3)
x=−10
Answer:
x=2 or x=−10
Answer:
-0.25 or 1/4
Step-by-step explanation:
Eh just know
Answer:
-When (2×-5) intersects at ×-axis the value of × will be zero.
=>F(×)=× 0=2×-5
hence,
0,=2×-5
5=2×
=>×=5/2
Step-by-step explanation:
hpe it hlps
