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Vinil7 [7]
3 years ago
7

-4+3x=8 solve plzzzz

Mathematics
2 answers:
Sophie [7]3 years ago
8 0
<h3>- 4 + 3x = 8</h3>

<h3>3x = 8 + 4</h3>

<h3>3x = 12</h3>

<h3>x = 12 ÷ 3</h3>

<h3>x = 4</h3>

hope that helps and please tell me if you need an explanation of the steps :))

jarptica [38.1K]3 years ago
3 0

Answer:

x=4

Step-by-step explanation:

-4+3x=8

+4      +4

<u>3x</u>=<u>12</u>

3x  3x

x=4

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A population of rabbits triples every month.the population starts with two rabbits.how many rabbits are there after 3 month's
Tresset [83]
The answer would be 54. Because you start with 2.
2x3 = 6
6x3 = 18
18x3 = 54
Each month it triples so you continue
to add 3 to each result.
7 0
3 years ago
Need help with all And have to show work
kari74 [83]
Altho' I can easily guess what you're supposed to do here, I must point out that you haven't included the instructions for this problem.

I'll help you by example.  Let's look at the first problem:

"Evaluate  6(z-1) at z-4."

Due to "order of operations" rules, we must do the work inside the parentheses FIRST.  Replace the z inside (z-1) with "-4".  We obtain

6(-4-1) = 6(-5) = -30 (answer.)

Your turn.  Try the next one.  If it's unclear, as questions.
8 0
3 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
How do I find the area
inn [45]
Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
(19m \times 11m) \div 2
\frac{209  }{2}

Answer:
104.5sq \: m
Hope this helped you
:D
8 0
3 years ago
Usain Bolt of Jamaica set a world record in 2009 for the 200- meter dash with a time of 19.19 seconds. What was his average spee
kirill [66]

Answer:

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Step-by-step explanation:

We use the following relation to solve this question:

v = \frac{d}{t}

In which v is the velocity(in m/s), d is the distance(in meters), and t is the time, in seconds.

Usain Bolt of Jamaica set a world record in 2009 for the 200- meter dash with a time of 19.19 seconds.

This means that d = 200, t = 19.19

So his average speed was of:

v = \frac{d}{t} = \frac{200}{19.19} = 10.42

His average speed was of 10.42 m/s

6 0
3 years ago
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