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Mila [183]
3 years ago
11

Hello Guys!

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

107 with a remainder of 201.

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Help ASAP please! Problem is on pictures below.
Elis [28]

Answer: figures C and D.


Explanation:


The question is which two figures have the same volume. Hence, you have to calculate the volumes of each figure until you find the two with the same volume.


1) Figure A. It is a slant cone.

Dimensions:

  • slant height, l = 6 cm
  • height, h: 5 cm
  • base area, b: 20 cm²

The volume of a slant cone is the same as the volume of a regular cone if the height and radius of both cones are the same.

Formula: V = (1/3)(base area)(height) = (1/3)b·h

Calculations:

  • V = (1/3)×20cm²×5cm = 100/3 cm³

2. Figure B. It is a right cylinder

Dimensions:

  • base area, b: 20 cm²
  • height, h: 6 cm

Formula: V = (base area)(height) = b·h

Calculations:

  • V = 20 cm²· 6cm = 120 cm³

3. Figure C. It is a slant cylinder.

Dimensions:

  • base area, b: 20 cm²
  • slant height, l: 6 cm
  • height, h: 5 cm

The volume of a slant cylinder is the same as the volume of a regular cylinder if the height and radius of both cylinders are the same.

Formula: V = (base area)(height) = b·h

Calculations:

  • V = 20cm² · 5cm = 100 cm³

4. Fiigure D. It is a rectangular pyramid.

Dimensions:

  • length, l: 6cm
  • base area, b: 20 cm²
  • height, h: 5 cm

Formula: V = (base area) (height) = b·h

Calculations:

  • V = 20 cm² · 5 cm = 100 cm³

→ Now,  you have found the two figures with the same volume: figure C and figure D. ←

7 0
4 years ago
Question attached,
alexandr1967 [171]

Answer:

Step-by-step explanation:

(a)\\ \\ (i)\ \sqrt{3}=3^p\\ \\ 3^{\frac{1}{2}}=3^p\\ \\ p=\frac{1}{2}\\ \\ (ii)\ \frac{1}{9}=3^q\\ \\ 3^{-2}=3^q\\ \\ q=-2\\ \\ (b)\\ \\ 3^{\frac{1}{2}(3^x)=\frac{1}{9}\\ \\ 3^{\frac{1}{2}+x}=3^{-2}\\ \\ \frac{1}{2}+x=-2\\ \\ x=-1.5

7 0
3 years ago
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