What did the doctor say after examining yunn yunsberger?

X^3 + 2x^2 – 24x<br><br> ^ <br> write the polynomial in factored form

BigorU [14]

Answer:

x(x+6)(x-4)

Step-by-step explanation:

They all have x in it, which means we can factor out x first.

x(x^2 + 2x -24)

Now we can factor out the inside doing algebra.

Since 6 multiplied by -4 gives us -24 and adding them gives us 2, 6 and -4 works. This means that we can factor out (x+6) and (x-4).

We still have to multiply the x from the beginning, giving us a final equation of

x(x+6)(x-4).

8 0

3 years ago

Can someone please help me with this

galina1969 [7]

Ooof, this is a lot! XD, anyway the answer are in the pictures.

8 0

3 years ago

There are four accent walls that need to be painted: cafeteria, gym, auditorium, and entrance. The art class is going to paint e

V125BC [204]

The probability of an ocean scene going on the gym wall is 16%

6 0

3 years ago

Read 2 more answers

Analyze the statement below and complete the instructions that follow. If a month is June, then it has 30 days. Write the contra

aleksley [76]

Note first that several months have 30 days (each): April, June and September.

(A) could not be correct, since the month in question could have 28, 29 or 31 days.

(B) See (A), above. If the month in question does not have 30 days, then the month could NOT be April, June or September. Reject (B).

(C) You do this one, similarly to my responses to (A) and (B), above.

(D) This one is true, since we know that June has 30 days. If the month in question does NOT have 30 days, then that month could not possibly be June.

6 0

4 years ago

Plz help

Angelina_Jolie [31]

Answer:

Part A

The two equations are;

d = 3 m/s × t for Boat A

d = 4.8 m/s × (t - 6 s) for Boat B

Part B

The solution to the system of equation are

t = 16 s and d = 48 m

Part C: The possible values of 't' for Boat A are 0 ≤ t ≤ ∞

The possible values of 't' for Boat B are 6 ≤ t ≤ ∞

Boat B timing starts when Boat B crosses the start line when t = 6 seconds

The solution of the system of equation indicates that Boat B and Boat A arrive at the same point, 'd' 48 meters from the start, 16 seconds from the time Boat A crosses the stat line

Step-by-step explanation:

The given parameters are;

The speed of Boat A = 3 m/s

The speed of Boat B = 4.8 m/s

The time Boat B crosses the start line = 6 seconds after Boat A crosses the start line

Part A

The two equations are;

For Boat A

d = 3 m/s × t...(1)

For Boat B

d = 4.8 m/s × (t - 6 s)...(2)

Where;

t = The time in seconds since Boat A crossed the start line

d = The distance traveled by the boat in meters

Part B

The system of equations from Part A is solved as follows;

d = 3 m/s × t and d = 4.8 m/s × (t - 6 s)

At the (common) solution point to the system of equation, we have;

d = 3 m/s × t, d = 4.8 m/s × (t - 6 s)

∴ 3 m/s × t = 4.8 m/s × (t - 6 s)

3·t m/s = 4.8·t m/s - 28.8 m

3·t m/s + 28.8 m = 4.8·t m/s

4.8·t m/s = 3·t m/s + 28.8 m; By transitive property of equality

4.8·t m/s - 3·t m/s = 28.8 m

1.8·t m/s = 28.8 m

t = 28.8 m/(1.8 m/s) = 16 s

t = 16 s.

d = 3 m/s × t = 3 m/s × 16 s = 48 m

d = 48 m

The solution of the system of equation is t = 16 s, d = 48 m

Part C: The possible values of 't' for Boat A are 0 ≤ t ≤ ∞

The possible values of 't' for Boat B are 6 ≤ t ≤ ∞

The timing variable, 't' for the equations of Boat A and Boat B is with reference to the time which Boat A crosses the start line, which is 6 seconds before Boat B, therefore, Boat B crosses the start line when t = 6 seconds

The solution of the system of equation represents that Boat B reaches Boat A at a point 48 meters from the start, 16 seconds from the time Boat A crosses the stat line.

4 0

3 years ago