Ask question

Ask question

All categories

3 years ago

15

A carnot cycle engine operates between a low temperature reservoir at 20°c and a high temperature reservoir at 800°c. if the eng

ine is required to output 20.0 kj of work per cycle, how much heat must the high temperature reservoir transfer to the engine during each cycle?

1 answer:

Bogdan [553]3 years ago

8 0

Adgjmptwadgjmtwmjdgamawtmtwjpadgtawpmpjgjdmgtmp487555454056704641

You might be interested in

Communicate the results

katen-ka-za [31]

What results do we communicate?

6 0

4 years ago

A 25-kg child sits at the top of a 4-meter slide. After sliding down, the child is traveling at 5 m/s. How much PE does he start

Semmy [17]

Daniddmelo says it right there, don't know why he got reported.

The potential energy (PE) is mass x height x gravity. So it would be 25 kg x 4 m x 9.8 = 980 joules. The child starts out with 980 joules of potential energy. The kinetic energy (KE) is (1/2) x mass x velocity squared. KE = (1/2) x 25 kg x 5 m/s2 = 312.5 joules. So he ends with 312.5 joules of kinetic energy. The Energy lost to friction = PE - KE. 980- 312.5 = 667.5 joules of energy lost to friction.

Please don't just copy and paste, and thank you Dan cause you practically did it I just... elaborated more? I dunno.

4 0

3 years ago

A torsion pendulum consists of an irregularly-shaped object of mass 20.0 kg suspended vertically by a wire of torsion constant 0

netineya [11]

Answer:

Rotational inertia of the object is, $I=0.023\ kg-m^2$

Explanation:

Given that,

Mass of the object, m = 20 kg

Torsion constant of the wire, K = 0.85 N-m

Number of cycles, n = 69

Time, t = 66 s

To find,

The rotational inertia of the object.

Solution,

There exists a relationship between the moment of inertia, time period and the torsion constant of the spring is given by :

$T=2\pi\sqrt{\dfrac{I}{K}}$

Here I is the moment of inertia

T is the time period, and it is equal to the number of cycles per unit time

$I=\dfrac{T^2K}{4\pi ^2}$

$I=\dfrac{(69/66)^2\times 0.85}{4\pi ^2}$

$I=0.023\ kg-m^2$

So, the rotational inertia of the object is $0.023\ kg-m^2$ .

7 0

4 years ago

The table below shows 4 examples of pairs of objects, their masses, and the distance between them. In which example is the gravi

svp [43]

Answer:

example two

Explanation:

They have the greatest masses and close proximety relative to the rest, (If you have two black holes each with a solar mass only 1 mile away from one another, they will be highly atracted and probly

orbit each other once a second or so. But now lets try to put the earth and moon one half mile away from each other, they orbit each other much much slower then the two black holes, its becuase the gigantic mass of the black holes overwalms the closser distance between earth and the moon

Have a great day,

enjoy life.

3 0

3 years ago

Help please I'm struggling.

Mrrafil [7]

Well, collinear points are points in same line,

that is a straight line is formed by connecting them,
here the line segment mE has point A,G,C,E so all these are collinear..

so, option c) E will be answer

hope it helped

4 0

3 years ago