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aleksklad [387]

4 years ago

6

Communicate the results

1 answer:

katen-ka-za [31]4 years ago

6 0

What results do we communicate?

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If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil

Nat2105 [25]

A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.

The answer is A) decrease

Take pushing a box, for example-- You push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!

( Mind marking me for branliest? ; ) )

4 0

3 years ago

What does it mean for forces to be in equilibrium?.

lapo4ka [179]

Explanation:

If the size and direction of the forces on the object are exactly balanced , then there is no net force acting on the object

8 0

3 years ago

Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn

rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary $N_p=300$

Numb er of turns in secondary $N_s=500$

Now consider second transformer

Number of turns in primary $N_p=250$

Number of turns in secondary $N_s=1000$

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

$\frac{N_p}{N_s}=\frac{V_p}{V_s}$

$\frac{250}{1000}=\frac{50}{V_s}$

$V_s=200volt$

So secondary voltage on second transformer is 200 volt

4 0

4 years ago

A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this

kondaur [170]

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{402}{603}$

$\lambda = 0.67\ m$

Number of anti nodes in the standing wave

$n=\dfrac{l}{\frac{\lambda}{2}}$

$n=\dfrac{2l}{\lambda}$

$n=\dfrac{2\times 1.33}{0.67}$

n =3.97= 4.

Number of antinodes is equal to 4.

7 0

3 years ago

Monochromatic light of wavelength 720 nm is incident on parallel slits, of width 0.420 mm, separated by 0.560 mm. A diffraction

ki77a [65]

Answer:

1.81×10^-4Io

Explanation:

Check attachment

4 0

4 years ago