I need help factoring this expression

In 1 minute, Alex can type 44 words. While working on a project, Alex types from 10:00 AM until 1 AM, He takes a break from 1 0:

viktelen [127]

Answer:

39600 words

Step-by-step explanation:

Given data

In 1 minute, Alex can type 44 words

from 10:00 AM until 1 AM= 15 hours

15 hours to minutes= 15*60= 900 minutes

Hence in In 1 minute, Alex can type 44 words

in 900 minutes he will type x words

cross multiply

x= 900*44

x= 39600 words

Hence he will type 39600 words

4 0

3 years ago

A study reported that the average age of menarche of girls entering the first year class of a small American private college in

Verizon [17]

Answer:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=12.98$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

4 0

3 years ago

Write an equation for a line g(x) perpendicular to f(x) = 4x − 5 and passing through the point (4, 20). plz.....

cluponka [151]

The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84

4 0

3 years ago

Resuelve los problemas de una bodega que exporta tomates al extranjero

Dovator [93]

Answer:

1. 34.42 Toneladas

2. 28.640 toneladas

3. 38 toneladas

4. $\frac{15}{10}$ o $1\frac{5}{10}$

5. $\frac{16}{6}$ o $2\frac{4}{6}$

6. $\frac{8}{4}$ o $2$

1.1 Solucioné el problema convirtiendo el .25 en fracción.

2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo

3.1 0.099

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{2}{3}$

0.7

0.75

1.1

$\frac{3}{2}$

Step-by-step explanation:

Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes $\frac{10}{3}$ entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería $3\frac{1}{3}$