Evaluate this expression. 3^-2

A line passes through (1, 8) and is perpendicular to the graph of y = 2x+1. What equation

Genrish500 [490]

Answer:

y = -1/2x + 17/2

Explanation:

y = 2x + 1 is in slope intercept form

in the equation y = mx+b, m is the slope, and in the equation m =2

the slope of a perpendicular line is the negative reciprocal of the other slope.

slope of perpendicular= -1/m = -1/2

y = -1/2x + b

now find b by substituting in (1,8) into the partial equation

8 = -1/2 + b

b = 8+ 1/2

b = 17/2

please give thanks :) hope this helps

5 0

3 years ago

Is this relation a function choose correct answer marking brainlist

Elan Coil [88]

The correct answer is d because every input is supposed to have exactly one output

5 0

2 years ago

Please help me with this geometry question. x and pr needed ao basically like this x=(answer), PR=(answer). Thank you

Dennis_Churaev [7]

Answer:

x = -1, PR = 38.

Step-by-step explanation:

As Q is the midpoint of PR

PQ = QR

6x + 25 = 16 - 3x

9x = -9

x = -1.

PR

= 6x + 25 + 16 - 3x

= 6(-1) + 25 + 16 - 3(-1)

= -6 + 25 + 16 + 3

= 38.

7 0

1 year ago

Which equation is not a linear function? y = x-2 y = 2x y = x2 y = x + 2

lora16 [44]

As they are written, they are all linear. I think you meant for the third one to be y=x^2. if that is true then y=x^2 is a quadratic and therefore is the answer

8 0

2 years ago

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

2 years ago