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Mrrafil [7]
3 years ago
7

Which equation describes how the parent function y=x^3, is vertically streched by a factor of 4

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

y=4x^{3}

Step-by-step explanation:

It is known that,

<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>

The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.

As, we have the function y=x^{3} which is stretched by a factor of 4.

Thus, the new function will be y=4x^{3}.

Hence, the equation for the vertical stretch is y=4x^{3}.

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Suppose f(x)=x^2.What is the graph of g(x)=f(5x)?
ZanzabumX [31]

Answer:

D

Step-by-step explanation:

g(x)=f(5x)

this means plugging in 5x for x in f(x):

g(x)=f(5x)=(5x)^2

which can be further simplified:

5^2x^2=25x^2

Since the coefficient of x being larger means a vertical stretch, the answer is D

example:

g(2)=f(5*2)=f(10)=f(10^2)=100

so for g(x), it has the coordinates (2,100), which is most definitely not C

5 0
3 years ago
Help please will mark brainliest!!!
wel
93.9 or 17702.3 I think it’s the long 1 tho
7 0
3 years ago
Which value of x would make TV=QS ?
sveticcg [70]
I believe it's c.10??
7 0
3 years ago
Estimate the student's walking pace, in steps per minute, at 3:20 p.m. by averaging the slopes of two secant lines from part (a)
ehidna [41]

This question is incomplete, the complete question is;

A student bought a smart-watch that tracks the number of steps she walks throughout the day. The table shows the number of steps recorded (t) minutes after 3:00 pm on the first day she wore the watch.

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

a) Find the slopes of the secant lines corresponding to the given intervals of t.

1) [ 0, 40 ]

11) [ 10, 20 ]

111) [ 20, 30 ]

b) Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part (a). (Round your answer to the nearest integer.)

Answer:

a)

1) for [ 0, 40 ], slope is 96

11) for [ 10, 20 ],  slope is 86.3

111) for  [ 20, 30 ], slope is 116.4

b) the student's walking pace is 101 per min

Step-by-step explanation:

Given the data in the question;

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

SLOPE OF SECANT LINES

1) [ 0, 40 ]

slope =  ( 7,128 - 3,288 ) / ( 40 - 0

= 3840 / 40 = 96

Hence slope is 96

11)  [ 10, 20 ]

slope = ( 5,522 - 4,659 ) / ( 20 - 10 )

= 863 / 10 = 86.3

Hence slope is 86.3

111)  [ 20, 30 ]

slope = ( 6,686 - 5,522 ) / ( 30 - 20 )

= 1164 / 10 = 116.4

Hence slope is 116.4

b)

Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part .

Since this is recorded after 3:00 pm

{ 3:20 - 3:00 = 20 }

so t = 20 min

so by average;

we have ( [ 10, 20 ] + [ 20, 30 ] ) /2

⇒ ( 86.3 + 116.4 ) / 2

= 202.7 /2

= 101.35 ≈ 101

Therefore, the student's walking pace is 101 per minutes

3 0
3 years ago
I am thinking of a number, let's call it x . If I increase twice my number by 5, the result is the same as if I triple my number
Mrrafil [7]

Answer: 6

Step-by-step explanation:

Let the number be x

If I increase twice my number by 5, the result is the same as if I triple my number and subtract 1. This can be formed into an equation as:

(2 × x) + 5 = (3 × x) - 1

2x + 5 = 3x - 1

5 + 1 = 3x - 2x

x = 6

The number you are thinking of is 6

4 0
3 years ago
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