Which equation describes how the parent function y=x^3, is vertically streched by a factor of 4
1 answer:
Answer:
Step-by-step explanation:
It is known that,
<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>
The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.
As, we have the function which is stretched by a factor of 4.
Thus, the new function will be .
Hence, the equation for the vertical stretch is .
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Answer:
The Taylor series of f(x) around the point a, can be written as:
Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as: