Answer:
2,075,673,600 batting orders may occur.
Step-by-step explanation:
The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:

First 8 batters
8 players from a set of 16. So

Last batter:
Any of the four pitchers.
How many different batting orders may occur?
4*518918400 = 2,075,673,600
2,075,673,600 batting orders may occur.