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ella [17]
2 years ago
7

A student ID number is a letter of the alphabet followed by 2 digits. How many different IDs are possible if the digits can be r

epeated?
Mathematics
1 answer:
mars1129 [50]2 years ago
4 0
First, there are 26 distinct alphabets and 10 distinct digit numbers.

Then, the first digit of ID has 26 possibilities.

For the rest of 2 digits, the total cases are 10*10 = 100 possibilities.

However, there are 10 cases are repeated when two digits are the same. so you have  to subtract it by 10

So answer will be 26 * (100-10) = 23400

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The price of an item has been reduced by 10%. The original price was $51. What is the prince of the item now?
AlekseyPX

Answer:

The new price is 45.90

Step-by-step explanation:

The original price is 51

Find the discount of 10 %

51*10%

51*.10

5.1

Subtract this from the original price

51- 5.1

45.9

The new price is 45.90

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2 years ago
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Help! What’s the y intercept of the linear equation 7+y=4.3x
Rasek [7]

Answer:

(0,-7)

Step-by-step explanation:

the y-intercept is found when the x-value is equal to 0. In this case, we are finding a coordinate pair. First, plug in 0 for x.

7+y=4.3(0)

simplify

7+y=0

subtract 7 from both sides

y=-7

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(0,-7)

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5th grade math. correct answer will be marked brainliest
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Answer:

Step-by-step explanation:

1\frac{1}{2} * \frac{1}{3} = \frac{3}{2}*\frac{1}{3}    cross cancel    then  you have  \frac{1}{2}   :)

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Find S30 HELPP. 10 points!<br> An arithmetic sequence has Si = -7 and S3 = 0.
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Step-by-step explanation:

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The sum of three numbers is 9.The sum of twice the first​ number, 4times the second​ number, and 5times the third number is 25.T
Karo-lina-s [1.5K]

Answer:

x = 6, y = 2, z = 1

Step-by-step explanation:

This is a system of 3 equations with 3 unknowns.  We need to first write the equations given the information and then solve them.

The first equation is the sum of 3 numbers, all unknown, is 9:

x + y + z = 9

The second equation is again a sum:

2x + 4y + 5z = 25

The third equation is the difference of only the first 2 numbers:

6x - y = 34

We will start with that last equation and solve it for y:

-y = -6x + 34 so

y = 6x - 34

Now we will go back to the first 2 equations and sub that 6x-34 in for each y.  The first equation then becomes:

x + 6x - 34 + z = 9 and 7x + z = 43

The second equation then becomes:

2x + 4(6x - 34) + 5z = 25 and 26x + 5z = 161

We will solve those 2 bold equations by addition/elimination:

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26x  + 5z = 161

Multiply the first equation through by -5 to get rid of the z's.  That equation then becomes:

 -35x  -  5z  =  -215

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Adding straight down the columns gives you

 -9x  =  -54 so

x = 6

Now we can plug that x value of 6 into any equation that has an x in it:

26(6) + 5z = 161 and

156 + 5z = 161 and

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We can use the x value only again in the equation we solved for y in the beginning:

y = 6(6) - 34 so

y = 36 - 34 and

y = 2

The solution to this system in coordinate form is

(6, 2, 1)

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3 years ago
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