All categories

3 years ago

Eight baseballs weight 40 ounces.How many pounds do 16 baseballs weight

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

6 0

Answer:

80 ounces

Step-by-step explanation:

If eight baseballs weigh 40 ounces, it means that there are 40 ounces in every eight baseballs.

40 ounces / 8 baseballs can be simplified to 5 ounces / 1 baseball.

So each baseball weighs 5 ounces.

If there were 16 baseballs, they would weigh 16 * 5 ounces.

16 * 5 = 80

16 baseballs weigh 80 ounces.

Please mark as Brainliest! :)

You might be interested in

A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the intercept

Helen [10]

The correct answer is 180°

6 0

2 years ago

Read 2 more answers

Please help 2 problems I really need it

sweet [91]

A) 50×12 b) 5×7. I think

3 0

3 years ago

Over a two-hour time period, a snail moved 108 inches. How far is this in yards?

kaheart [24]

The snail moved 108 inches
108/36=3 yards
as 1 yard=36 in

5 0

2 years ago

Is √1/9 greater less than or equal to 1/4

victus00 [196]

Answer:

Greater:

$\sqrt{1/9} > 1/4$

Step-by-step explanation:

$\sqrt{\frac{1}{9} } =\frac{\sqrt{1} }{\sqrt{3} } =\frac{1}{3}$

1/3 is greater than 1/4

Hope this helps

7 0

1 year ago

Y=x^2-6x+3 help write the vertex form of the equation

Artist 52 [7]

Answer:

$y=(x-3)^2-6$

Step-by-step explanation:

$y=x^2-6x+3$

This is written in the standard form of a quadratic function:

$y=ax^2+bx+c$

where:

ax² → quadratic term
bx → linear term
c → constant

You need to convert this to vertex form:

$y=a(x-h)^2+k$

where:

(h,k) → vertex

To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

$x=-\frac{b}{2a}$

Using your original equation, identify the a, b, and c terms:

$a=1\\\\b=-6\\\\c=3$

Insert the known values into the equation:

$x=-\frac{(-6)}{2(1)}$

Simplify. Two negatives make a positive:

$x=\frac{6}{2} =3$

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

$y=3^2-6(3)+3$

Simplify using PEMDAS:

$y=9-18+3\\\\y=-9+3\\\\y=-6$

The value of y is -6 (3,-6). Insert these values into the vertex form:

$(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)$

Insert the value of a and simplify:

$y=(x-3)^2-6$

:Done

6 0

2 years ago