Step-by-step explanation:
again, 2 unknowns.
x = number of 2- points baskets
y = number of 3- points baskets
we know they hit the basket 37 times in a so far unknown mixture of 2-point and 3- point throws.
x + y = 37
which gives us e.g.
x = 37 - y
and we know that with this unknown mixture they scored 80 points.
so,
2x + 3y = 80
as every successful 2-points throw scores 2 points, and every successful 3-points throw scores 3 points.
so, again our 2 equations :
x = 37 - y
2x + 3y = 80
remember, we prepared the first equation so that it gives us already an identity expressing one variable by the other. and that we use in the second equation :
2×(37 - y) + 3y = 80
74 - 2y + 3y = 80
74 + y = 80
y = 6
and from
x = 37 - y
we get
x = 37 - 6 = 31
so, they had 31 2-points throws and 6 3-points throws.
4mins---->12 cars
6mins---->(6*12/4)=18
4mins---->12
5mins---->(5*12/4)=15
And so on
2x+20=58 then your would subtract 20 from 58 which would turn into 38 and your would divide 38/2 it would be 19 so the answer is x=19 if I’m not mistaken this is correct hope this helps
It depends on the question . What is the question asking about?
