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katrin2010 [14]

3 years ago

12

In a prize drawing at a fundraiser, you choose three different numbers from 1 to 8. How many ways are there to choose three numb

ers?

1 answer:

Sergeu [11.5K]3 years ago

8 0

For the first number you can choose from 8, for the second number only 7, for the third number only 6. So the number of combinations is 8x7x6=336

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Answer:

the side length is 3.

Step-by-step explanation:

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4 0

3 years ago

Is 2x+10 = -2(x-5) equals

faust18 [17]

First distribute -2 to both x and -5

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False is your answer

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3 0

3 years ago

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At the movie theatre, child admission is $5.10 and adult admission is $9.70. On Thursday, 128 tickets were sold for a total sale

kvv77 [185]

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53

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Let x be the number of children tickets sold and y be the number of adult tickets sold. Then

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From the first equation,

x=128-y,

then

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3 years ago

What is m<BCD<br>OA) 80°<br>OB) 90°<br>C) 100°<br>D) 110°

wlad13 [49]

Answer:

D

Step-by-step explanation:

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