Explanation:
The reaction given is;
TiCl4 + H2O --> TiO2 + HCl
The reaction is not balanced, upon balancing it is given as;
TiCl4 + 2H2O → TiO2 + 4HCl
a. How many moles of H2O are needed to react with 6.50 moles of TiCl4?
From the reaction;
1 mol of TiCl4 requires 2 mol of H2O
6.50 mol of TiCl4 would require x mol of H2O
1 = 2
6.5 = x
x = 6.5 * 2 / 1 = 13.0 mol
b. How many moles of HCl are formed when 8.44 moles of TiCl4 react?
From the equation of the reaction;
1 mol of TiCl4 reacts to form 4 mol of HCl
8.44 mol of TiCl4 reacts to form x mol of HCl
1 = 4
8.44 = x
x = 8.44 * 4 / 1 = 33.76 mol
Answer:
0.21mol Ar (g)
Explanation:
To convert from litres to moles at STP we must divide the amount of litres by 22.4.
4.7 / 22.4 = 0.21mol Ar (g)
Answer:
6.53g of K₂SO₄
Explanation:
Formula of the compound is K₂SO₄
Given parameters:
Volume of K₂SO₄ = 250mL = 250 x 10⁻³L
= 0.25L
Concentration of K₂SO₄ = 0.15M or 0. 15mol/L
Unknown:
Mass of K₂SO₄ =?
Methods:
We use the mole concept to solve this kind of problem.
>>First, we find the number of moles using the expression below:
Number of moles= concentration x volume
Solving for number of moles:
Number of moles = 0.25 x 01.5
= 0.0375mole
>>Secondly, we use the number of moles to find the mass of K₂SO₄ needed. This can be obtained using the expression below:
Mass(g) = number of moles x molar mass
Solving:
To find the molar mass of K₂SO₄, we must know the atomic mass of each element in the compound. This can be obtained using the periodic table.
For:
K = 39g
S = 32g
O = 16g
Molar mass of K₂SO₄ = (39x2) + 32 + (16x4)
= 78 +32 + 64
= 174g/mol
Using the expression:
Mass(g) = number of moles x molar mass
Mass of K₂SO₄ = 0.0375 x 174 = 6.53g
Answer:
0.006342moles
Explanation:
1000ml of NaOH contain 0.151moles
42ml of NaOH contain (42*0.151)/1000 moles
=0.006342moles