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2 years ago

NO BOTS! Determine the total net force and the direction of movement for the situation.

Chemistry

1 answer:

pychu [463]2 years ago

5 0

Answer:

5N Left (the direction of friction)

Explanation:

Looking at the normal force and the gravitational force, they are both of equal magnitude (3N), and are in opposite directions ( up and down). This means they cancel out - their overall force is 0.

Moving on to the sideways forces, we only have friction (5N). There is no force to the right to cancel this out, so the overall force must be 5N left.

Hope this helps! Let me know if you have any questions :)

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Which statements are true about reversible reactions?

umka21 [38]

Answer:

Reversible reactions exhibit the same reaction rate for forward and reverse reactions at equilibrium.

Reversible reactions exhibit constant concentrations of reactants and products at equilibrium

Explanation:

A reversible reaction is a reaction that can proceed in both forward and backward direction.

Equilibrium is attained in a chemical system when there is no observable change in the properties of the system.

At equilibrium, a reversible reaction is occurring in at same rate. That is, the forward and backward reaction is occurring at the same rate. As the rate of the forward and backward reaction remains the same, the concentrations of the reactants and products will also be the same in order for the equilibrium to be maintained.

5 0

2 years ago

Read 2 more answers

An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of

RSB [31]

Answer:

$V=0.0310L=3.10mL$

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

$n_{acid}=n_{KOH}$

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

$n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol$

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

$V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL$

Best regards!

7 0

2 years ago

A sample of helium has a volume of 50.00 L at STP. How many helium atoms are in the sample? Show work

Setler79 [48]

Answer:

Explanation:

molar volume at STP=22.4 L

given volume=50.0 L

number of moles=given volume/molar volume

number of moles=50.0/22.4

number of moles=2.2

1 mole of helium =6.023*10^23 atoms

2.2 moles of helium =6.023*10^23*2.2=1.3*10^24

therefore 50.0 L of helium contain 1.33*10^24 atoms

4 0

2 years ago

PLEASEEEEE HELP MATH EXPERTS<br><br> What is the value of x?

diamong [38]

X=107 because the sides of a hexagon must add up to 720

6 0

2 years ago

You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p

Elenna [48]

Answer:

<u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

$PV=nRT$

Where:

P = pressure = 1.25 atm
V = volume = 25.2 liter
R = Universal constant of gases = 0.08206 atm-liter/K-mol
T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
n = number of moles

Solving for n:

$n=\frac{PV}{RT}$

Substituting:

$n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol$

8 0

2 years ago