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2 years ago

3. If you want to produce 12.6 g of HCl, how many grams of PCls will you need?

Chemistry

1 answer:

Ratling [72]2 years ago

4 0

35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

<h3>Equation of the reaction</h3>

The equation of the reaction is given below:

PCl₅ + H2O ---> POCl₃ + 2 HCl

<h3>How to calculate grams of PCl₅ required to produce 12.6 g of HCl</h3>

Molar mass of PCl₅ = 208.5 g

Molar mass of Hcl = 36.5 g

Moles of HCl = mass / molar mass

Moles of HCl = 12.6 / 36.5

moles of HCl = 0.345 moles

2 moles of HCl are produced by 1 mole of PCl₅

0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅

Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅

Mass of PCl₅ = 35.9 g of PCl₅

Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

Learn more about mass and molar mass at: brainly.com/question/15476873

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2 years ago

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Explanation :

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The combined gas equation is,

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$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

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Now put all the given values in the above equation, we get:

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Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

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$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

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