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ohaa [14]
2 years ago
8

3. If you want to produce 12.6 g of HCl, how many grams of PCls will you need?

Chemistry
1 answer:
Ratling [72]2 years ago
4 0

35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

<h3>Equation of the reaction</h3>

The equation of the reaction is given below:

PCl₅ + H2O ---> POCl₃ + 2 HCl

<h3>How to calculate grams of PCl₅  required to produce 12.6 g of HCl</h3>

Molar mass of PCl₅ = 208.5 g

Molar mass of Hcl = 36.5 g

Moles of HCl = mass / molar mass

Moles of HCl = 12.6 / 36.5

moles of HCl = 0.345 moles

2 moles of HCl are produced by 1 mole of PCl₅

0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅

Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅

Mass of PCl₅ = 35.9 g of PCl₅

Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

Learn more about mass and molar mass at: brainly.com/question/15476873

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i hope this helps

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3 0
3 years ago
You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
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Answer:

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Explanation:

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The total volume of the pool is:

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5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>

These moles comes from

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Thus:

1,00x10⁻² moles of H⁺ × \frac{1 H_{2}SO_{4} moles}{2H^+ mole} = <em>5,00x10⁻³ moles of H₂SO₄</em>

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × \frac{98,1g}{1mol} × \frac{100 gsolution}{12 g H_{2}SO_{4} } × \frac{1mL}{1,080 g} = <em>3,78 mL of 12,0wt% H₂SO₄</em>

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I hope it helps!

5 0
3 years ago
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