35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
<h3>Equation of the reaction</h3>
The equation of the reaction is given below:
PCl₅ + H2O ---> POCl₃ + 2 HCl
<h3>How to calculate grams of PCl₅ required to produce 12.6 g of HCl</h3>
Molar mass of PCl₅ = 208.5 g
Molar mass of Hcl = 36.5 g
Moles of HCl = mass / molar mass
Moles of HCl = 12.6 / 36.5
moles of HCl = 0.345 moles
2 moles of HCl are produced by 1 mole of PCl₅
0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅
Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅
Mass of PCl₅ = 35.9 g of PCl₅
Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
Learn more about mass and molar mass at: brainly.com/question/15476873
