Express 3.3.3.5.5 using exponents
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The slope of the line shown in the figure having equation x + 2y = 0 is 1/2.
The point A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and Point C is at ( -2 , 2 ).
Let point D be at ( -4 , 1 ).
Now the new triangle is ΔBDA and the corner points are A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and point D is at ( -4 , 1 ).
The equation of line passing through two points is given by:
The equation of line passing through two points A( -2 , 1 ) and B( -4 , 2 ) IS
y - 1 = ((2-1)/(-4-(-2))) (x-(-2))
y - 1 = (1/(-2)) (x+2)
2y -2 = -x -2
x + 2y = 0
The equation of straight line is x + 2y = 0
The equation in slope intercept form can be written as,
y = x/2 + 0
Slope = m = 1/2
Intercept = c = 0
So, we can conclude that 1/2 is the slope of the line .
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