Please help me I need this done<br> -Inequalities

Substitution Method. Help please? #5 please!

s344n2d4d5 [400]

Switch the second equation to equal y so...
y=-2x-3
then plug in for y in the first equation
2x+4(-2x-3)=6
2x-8x-12=6
-6x=18
x=-3
now plug in for y
2(-3)+y=-3
-6+y=-3
y=3

answer (-3,3)

8 0

2 years ago

Graphs and equations of lines

dmitriy555 [2]

Answer:

a) $y = -\frac{3}{4} x + 5$

b) $y = 6x-18$

c) $y = \frac{4}{5} x+\frac{19}{5}$

Step-by-step explanation:

a) The slope / gradient is the coefficient of $x$ , so for a) it will be $y=-\frac{3}{4} x + C$ .

C is the y-intercept, so the full equation will be $y = -\frac{3}{4} x + 5$ .

b) Again, since the slope is 6, we know the coefficient of $x$ will be 6.

Now, we have a point on the line and so far, we know the equation is $y=6x+c$ . The coordinates of the point are (2,-6). So now we substitute the y and x values into the equation in order to find C.

$-6 = 6(2)+C$

$-6 = 12+C$

$C = -18$

$y = 6x-18$

c) To find the gradient we must use the formula $\frac{rise}{run}$ .

rise = change in y value

run = change in x value

so, the gradient $= \frac{7-3}{4-(-1)} = \frac{4}{5}$

Now the equation is $y = \frac{4}{5} x +C$

Again, to find C we substitute any of the coordinates into the equation. I will use (-1,3).

$3 = \frac{4}{5} (-1) +C$

$3 + \frac{4}{5} =C$

$C =\frac{19}{5}$

so c) is $y = \frac{4}{5} x+\frac{19}{5}$

6 0

2 years ago

Round 3.962 to the nearest tenths

gayaneshka [121]

It would be 4.0

please can i have a brailiest

3 0

2 years ago

Read 2 more answers

Identify and calculate the area and perimeter for each polygon

irga5000 [103]

Identify and calculate formulas and examples...

Hope this helps ;)

7 0

3 years ago

The vector v⃗ in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

allsm [11]

The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis is: (0, -1/2, √3/2).

<h3>Vector</h3>

a. Vector (v)

Vector (v)=v (cos Ф, sin Ф)

V=1 while the counterclockwise angle that is measured from positive x=Ф=π/4

Hence:

Vector=3(cos π/4, sinπ/4)

Vector=(3/√2, 3√2)

b. Vector w:

Vector w=1(0, cos 2π/3, sin2π/3)

Vector w=(0, -1/2, √3/2)

Therefore the vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector ws: (0, -1/2, √3/2).

The complete question is:

Resolve the following vectors into components:

a. The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

(b) The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis.

Learn more about vector here:brainly.com/question/25705666

#SPJ1

5 0

1 year ago

Please help me I need this done -Inequalities