All categories

3 years ago

A coin is tossed 3 times. What is the probability that the number of tails obtained will be between 1 and 3 inclusive?

Mathematics

1 answer:

LekaFEV [45]3 years ago

5 0

Answer: $\dfrac{7}{8}$

Step-by-step explanation:

Given : When a coin is tossed twice , the total outcomes will become

HHH , HHT , HTH , THH , TTH , THT , HTT ,TTT

Total outcomes = 8

Favorable outcomes to obtain 1 and 3 inclusive = HHT , HTH , THH , TTH , THT , HTT ,TTT

Number of favorable outcomes = 7

Probability that the number of tails obtained will be between 1 and 3 inclusive = $\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$=\dfrac{7}{8}$

Hence, the probability that the number of tails obtained will be between 1 and 3 inclusive $=\dfrac{7}{8}$

You might be interested in

Find the prime factorization of 210.

Xelga [282]

5 x 2 x 7 x 3
Hope it helped! :)

8 0

3 years ago

Read 2 more answers

Perpendicular lines are lines that ___ ?

konstantin123 [22]

Answer:

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Is this sequence arithmetic, geometric, or neither? 45,50,65,70,85

Usimov [2.4K]

I think it is arithmetic

3 0

3 years ago

A spinner numbered 1 through 12 is spun. Find the probability that

anastassius [24]

Answer:

$\dfrac{1}{6}$

Step-by-step explanation:

Let A be the event of getting an odd number.

P(A) be the probability of getting an odd number.

Total odd numbers here are 6 i.e. $\{1,3,5,7,9,11\}$

Here, total numbers in the game are 12 i.e $\{1,2,3,....,12\}$ .

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}$

Let B be the event of getting 11.

P(B) be the probability of getting 11.

Total number of possible cases is 1.

$P(B) = \dfrac{1}{12}$

$P(A \cap B)$ is the probability that we get 11 and an odd number.

Possible number of cases = 1

$P(A\cap B) = \dfrac{1}{12}$

P(B/A) is the probability that we get an 11 given that it is an odd number.

$P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}$

Hence, P(B/A) = $\dfrac{1}{6}$

4 0

3 years ago

Read 2 more answers

Mr. Greenjeans planted 6 different crops on 2 acres of land. If half of it was planted with green beans, how many acres were pla

scoundrel [369]

If half of two acres was planted with green beans, the answer would be one acre

5 0

3 years ago