Question

A coin is tossed 3 times. What is the probability that the number of tails obtained will be between 1 and 3 inclusive?

Answer 1

Answer: $\dfrac{7}{8}$

Step-by-step explanation:

Given : When a coin is tossed twice , the total outcomes will become

HHH , HHT , HTH , THH , TTH , THT , HTT ,TTT

Total outcomes = 8

Favorable outcomes to obtain 1 and 3 inclusive = HHT , HTH , THH , TTH , THT , HTT ,TTT

Number of favorable outcomes = 7

Probability that the number of tails obtained will be between 1 and 3 inclusive = $\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$=\dfrac{7}{8}$

Hence, the probability that the number of tails obtained will be between 1 and 3 inclusive $=\dfrac{7}{8}$