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3 years ago

A number divided by 40 has a quotient of 6 with a remainder of 16.Ffind the number

2 answers:

4 0

In order to figure out your number you need to set up an equation with a variable. In this case it would look like this

$(40*6)+16=x$

Solve for x.

$(40*6)+16=x$
$(240)+16=x$
$256=x$

Your answer should be 256.

AlekseyPX3 years ago

3 0

(40*6)+16=X
240+16=X
256=X
The number is 256.

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The line about which a three-dimensional figure is rotated to obtain an object identical to the original is a(n) horizontal plane.

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3 years ago

The Heads Up Salon charges a stylist $50 a day to rent a station at the salon. Jenny, one of the stylists, makes $25.50 for each

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Answer:

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3 years ago

PLEASE HELP

enyata [817]

Answer:

There are 24 ways to select one book of each type.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

It is provided that there are 6 different biographies and 4 different mystery novels on a bookshelf.

Compute the number of ways to select a biography as follows:

Number of ways to select a biography =

$={6\choose 1}\\\\=\frac{6!}{1!(6-1)!}\\\\=\frac{6\times 5!}{1\times 5!}\\\\=6$

There are 6 ways to select a biography.

Compute the number of ways to select a mystery novel as follows:

Number of ways to select a mystery novel =

$={4\choose 1}\\\\=\frac{4!}{1!(4-1)!}\\\\=\frac{4\times 3!}{1\times 3!}\\\\=4$

There are 4 ways to select a mystery novel.

Then the total number of way to select one book of each type is:

${6\choose 1}\times {4\choose 1}=6\times 4=24$

Thus, there are 24 ways to select one book of each type.

6 0

3 years ago

The number .0100100010001.... can be classified as

dusya [7]

1.00100010001 x 10^-2

8 0

3 years ago

Rewrite the quadratic function in vertex form (which is also called a standard form) and give the vertex.

jasenka [17]

The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

<h3>How to rewrite the quadratic function?</h3>

The quadratic function is given as:

f(x) = x^2 - 3x

Differentiate the function

f'(x) = 2x - 3

Set the function to 0

2x - 3 = 0

Add 3 to both sides

2x = 3

Divide by 2

x = 3/2

Set x = 3/2 in f(x) = x^2 - 3x

f(x) = 3/2^2 - 3 * 3/2

Evaluate

f(x) = -9/5

So, we have:

(x, f(x)) = (3/2, -9/5)

The above represents the vertex of the quadratic function.

This is properly written as:

(h, k) = (3/2, -9/5)

The vertex form of a quadratic function is

f(x) = a(x - h)^2 + k

So, we have:

f(x) = a(x - 3/2)^2 - 9/5

In f(x) = x^2 - 3x,

a = 1

So, we have:

f(x) = (x - 3/2)^2 - 9/5

Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5