Answer:
An electric current is a flow of electrons. Elements that readily give up electrons (the metals) can carry electric current because their electrons can flow freely. ... They hold onto their electrons so they cannot flow.
Explanation:
The given question is incomplete. The complete question is as follows.
The solubility product of calcium fluoride () is at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?
Explanation:
Reaction equation for the given chemical reaction is as follows.
Therefore, expression for will be as follows.
=
Also, moles of per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]
=
=
Hence,
=
= M
Now, moles of per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]
=
= M
Also,
=
= M
Hence, ionic product =
=
=
As, the ionic product is less than the , this means that the fluoride will be soluble in water containing the calcium.
For each shift, you will earn 12/60*75=15 dollars=60 quarters. If the laundry is 12 quarters per load, you can make 60/12=5 loads. If the laundry is 16 quarters, you can make 60/16=3.75 loads. You can pay only 3 loads.
I'm pretty sure your answer should be CaCl2. Hope this helps! =^-^= (if I need to explain more just let me know.)
Answer:
i need more to solve this
Explanation: