answer:
oops, I accidentally messed this one up, so sorry
This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked.
Informtion needed:
Acceleration due to gravity = 9.81m/s^2
Formula:
Hmax = ((V^2)(sin(angle))^2)/2g
Hmax = ((50^2)(sin45)^2)/(2*9.81) = 63.71 or letter B 63.5 m is the closest answer.
Answer:
1 4/17
Step-by-step explanation:
3 1/2 ÷ 2 5/6
= 7/2 ÷ 17/6
= 7/2 * 6/17
= 21/17
= 1 4/17
Answer:
slope -1/2, y-intercept: 1
Step-by-step explanation:
1. y-intercept is the point where the line crosses the y axis. Line crosses y axis at (0,1).
2. Equation of a slope for a line given two points on the line is (y2-y1)/(x2-x1). We'll use (0,1) and (2,0).
3. Set one point as (x1, y1) and the other as (x2, y2). The way you assign them doesn't matter, as long as the 0 and 1 and the 2 and 0 remain together. We'll make (0,1) = (x1, y1) and (2,0) = (x2, y2).
4. Plug in the points for the variables in the equation they correspond to.
5. Solve: (0-1)/(2-0)
=-1/2
