Question

Kim surveyed the students at her school to find out if they like hotdogs and/or burgers. The table below shows the results of the survey:
If a student likes hotdogs, what is the probability that student also likes burgers?

A- 93.8%

B- 50.7%

C- 42.1%

D- 39.5%

Answer 1

The answer is 42.1% that is pretty easy

Answer 2

Answer: C- 42.1%

Step-by-step explanation:

Let H represents the event of liking hotdogs, B represents the event of liking burger and S represents total number of students,

Thus, by the given table,

n(H) = 76, n(S) = 150, $n(H\cap B) = 32$

⇒ $P(H)=\frac{n(H)}{n(S)}=\frac{76}{150}$

Also,

$P(H\cap B) = \frac{n(H\cap B)}{n(S)}= \frac{32}{150}$

Thus, by the definition of conditional probability,

The probability of liking burger when it is given that the student likes the hotdgs,

$P(\frac{B}{H})=\frac{P(H\cap B)}{P((H)}$

$=\frac{32/150}{76/150}$

$=\frac{32}{76}$

$=0.421052632$

$=42.1052632\%\approx 42.1\%$

⇒ Option C is correct.