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QveST [7]
3 years ago
7

If 15% of a number is 30 and 40% of the same number is 80, find 25% of that number.

Mathematics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

50

Step-by-step explanation:

let the number be x

15% of x= 0.15x

0.15x=30

(divide both sides by 0.15)

x= 200

25% of 200 = 25/100 *200

= 50

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The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?
bearhunter [10]

Answer:

The student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

P = 2l + 2w

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are \sqrt{50a^3b^2}  and  \sqrt{200a^3}\:\:.

Here is the student's solution:

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

                                 =30ab\sqrt{2a}          

The student made an error in calculating 30ab\sqrt{2a}+20a\sqrt{2a} , because 30ab\sqrt{2a}+20a\sqrt{2a} are not like terms.

Hence, 30ab\sqrt{2a}+20a\sqrt{2a} can not be simplified to 30ab\sqrt{2a}

Therefore, the student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

7 0
3 years ago
Read 2 more answers
Helppp asapppppppppp
LuckyWell [14K]

Answer:

put a point on the 9 (the line on the left of 10) and on the -6 (the line to the left of -5).

a. 9 is located to the right of -6

b. use the symbol >

Step-by-step explanation:

3 0
2 years ago
What is the coefficient in the expression y + 14?
Lady bird [3.3K]

Answer:

1

Step-by-step explanation:

y + 14

=> 1(y) + 14

=> Coefficient = 1

5 0
2 years ago
Please help me with this
alexandr402 [8]

Answer:

i wish i could help-

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. Yo
Arlecino [84]

If two triangles are similar then the corresponding sides are in proportion. Thus,

AB / AU = BC / UV = AC / AV

AB / (20x+108) = 703 / 444

Where AB is equivalent to:

AB = AU + UB

AB = 20x + 108 + 273

AB = 20x + 381

Therefore going back to the first equation:

(20x + 381) / (20x + 108) = 703/444

444 (20x + 381) = 703 (20x + 108)

8880x + 169164 = 14060x + 75924

14060x - 8880x = 169164 – 75924

5180 x = 93240

x = 93240 / 5180

<span>x = 18</span>

4 0
3 years ago
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