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lakkis [162]
3 years ago
14

Solve 2^16x=16^2x for x

Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
2^(16x)=16^(2x)


16=2⁴

2^(16x)=(2⁴)^(2x)
2^(16x)=2^(4*2x)
2^(16x)=2^(8x)

Therefore:
if a^n=a^m  ⇒n=m

16x=8x
16x-8x=0
8x=0
x=0/8=0

Answer: x=0
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yKpoI14uk [10]
I just had this question for homework too!

c = 4v + 1
v + c = 121

Now use substitution.

v + 4v + 1 = 121
5v + 1 = 121
5v = 120
v = 24

The answer is 24.
6 0
3 years ago
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Can someone please write out the decimal 112.001 as a fraction? And it would really really help me a lot if you could explain ho
iragen [17]

So let's leave the 112 aside for now. The question then becomes how to write the decimal 0.001 as a fraction. The key is to remember that

0.x  corresponds to "tenths" so x/10

0.0x corresponds to "hundredths" --> x/100

0.00x corresponds to "thousandths" --> x/1000

The number 0.001 is just 1 thousandth, or 1/1000

Now back to 112.001. You can write it as

112/1 + 1/1000 =

(112,000+1)/1000 =

112,001/1000  (the fraction you were looking for)

Let me know if you have questions

6 0
3 years ago
" A car is travelling around a horizontal circular track with radius r = 230 m at a constant speed v = 17 m/s as shown. The angl
Luda [366]
R = 230 m
v = 17 m/s

Formula: |Ac| = v^2 / r

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|Ac| = v^2 / r = (17m/s)^2 / (230m) = 1.257 m/s^2

Components:

cos(25) = - [ x-component / |Ac| ] => x-component = -|Ac|*cos(25)
sin(25)  = - [y-component / |Ac| ] => y-component = - |Ac|*sin(25)

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Point B

|Ac| = 1.256

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7 0
3 years ago
If dy/dx = X2 + 4, What is the value of y?
uranmaximum [27]
Antideritiive
antideritive of x^n is \frac{x^{n+1}}{n+1}
antiderititve of a constant is that constant times x
so

antideritive of x^2 is \frac{x^{2+1}}{2+1}=\frac{x^{3}}{3}
andtideritivee of 4 is 4x

total is
y= \frac{x^3}{3}+4x+C

D is answer
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3 years ago
A printer situated at point P is 5 feet from ad and 5 feet from DC plot point P on the coordinate plane and give the coordinates
Delvig [45]
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These lines are the boundaries. Point P is located within said boundaries.

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3 0
3 years ago
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