How to write 0.632 in wordform<br> please show an example

The first day, Brian saw 31 birds and twice as many squirrels as birds. The second day, Brian saw 20 birds and 42 squirrels. Whi

ladessa [460]

Answer: A good estimation would be about 150.

Step-by-step explanation:

To estimate we can round instead of using exact numbers.

First day he saw about 30 birds and twice as many squirrels, meaning about 60 squirrels. This is about 90 total when added together.

Second day he saw 20 birds and about 40 squirrels so about 60 when added together.

Add day one and day two totals for...

90+60=150

8 0

3 years ago

Which expressions are equivalent to 2^5 2^4

KIM [24]

Answer with explanation:

The given expression is

$=2^5 \times 2^4$

→As, multiplication of real number follows Commutative property.

Which states that, if a and b are any two real numbers , then

a × b= b × a

The Expression equivalent to ,the above expression are

$1. 2^4 \times 2^5\\\\ 2. 2^5=32 \text{and} 2^4=16, \text{So} 2^5 \times 2^4=32 \times 16=512$

5 0

3 years ago

Read 2 more answers

The population of cats that are rescued every year is currently 50,000 and declines at a rate of 1.2% every year. This models

larisa86 [58]

This models exponential decay.

8 0

3 years ago

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

$E(X)=\sum x_i p_i$

where

$x_i$ are all the possible values that the variable X can take

$p_i$ is the probability that $X=x_i$

Therefore in this problem, the expected value of MIguel's score is given by:

$E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55$

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

$E(X)=4.2$

- Instead, if the long hit fails, the expected value of X is

$E(X)=5.4$

Here we also know that the probability of a successfull long hit is

$p(L)=0.4$

Which means that the probabilty of an unsuccessfull long hit is

$p(L^c)=1-p(L)=1-0.4=0.6$

Therefore, the expected value of X if Miguel chooses the long hit approach is:

$E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92$

In part 1) of the problem, we saw that the expected value for the short hit was instead

$E(X)=4.55$

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0

3 years ago

What is the diameter of a circle with a circumference of 12 pii units

klemol [59]

The diameter is equal to 12.

5 0

3 years ago

How to write 0.632 in wordform please show an example