Answer:
Explanation:
public class Main
{
public static void main(String[] args) {
System.out.println("Test Class:");
Name name = new Name("Dayanand","Ghelaro");
System.out.println("First Name : "+name.getFirstName());
System.out.println("Last Name : "+name.getLastName());
}
}
class Name{
private String firstName; // first name field
private String lastName; // last name field
public Name(String firstName, String lastName){
this.firstName = firstName;
this.lastName = lastName;
}// end of constructor
public String getFirstName(){
return this.firstName;
} // end of method
public String getLastName(){
return this.lastName;
}// end of method
}// end of Name class
Answer:
Its data sets are at least a petabyte in size.
Explanation:
Big data data sets are of huge size to perform the computations using modern techniques.
Answer:
19.95
Explanation:
Power ratio (in db) = 10 * log [P(out)/P(in)]
Here, P(in) and P(out) correspond to input and output power in Watts respectively.
This implies, 13 db = 10 * log [P(out)/P(in)]
Rearranging, log [P(out)/P(in)] = (13/10)
Or, P(out)/P(in) = 10 ^ 1.3 = 19.95
But, P(out)/P(in) corresponds to the power ratio of output and input power.
So the required power ratio corresponds to 19.95
Converting a decimal number into binary would be:
192/2= 96 remainder=0
96/2= 48 remainder=0
48/2=24 remainder=0
24/2=12 remainder=0
12/2=6 remainder=0
6/2=3 remainder=0
3/2=1 remainder=1
1/2= 0 remainder=1
The binary number would be: 11 00 00 00
For 16
16/2=8 remainder=0
8/2=4 remainder=0
4/2=2 remainder=0
2/2=1 remainder=0
1/2= 0 remainder=1
The binary would be: 00 01 00 00
For 3
3/2=1 remainder=1
1/2= 0 remainder=1
The binary would be: 00 00 00 11
For 1
1/2= 0 remainder=1
The binary would be: 00 00 00 01
The binary number would be:
11000000.00010000.00000011.00000001
1. Fujifilm X-T4
2. Blackmagic Pocket Cinema Camera 6K
3. Nikon Z6 II
4. Sony a7S III
5. Panasonic Lumix S1H
6. Canon EOS R5
7. Sony Alpha 1
8. Blackmagic URSA Mini Pro 12K
9. Canon C300 Mark III
10. ARRI ALEXA Mini LF
