1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saw5 [17]
3 years ago
11

Using C#, declare two variables of type string and assign them a value "The "use" of quotations causes difficulties." (without t

he outer quotes). In one of the variables use quoted string and in the other do not use it.
Computers and Technology
1 answer:
stich3 [128]3 years ago
8 0

Answer:

Let the two string type variables be var1 and var2.  The value stored in these two variables is : The "use" of quotations causes difficulties.

  • The variable which uses quoted string:

          string var1 = "The \"use\" of quotations causes difficulties.";  

  • The variable which does not use quoted string:

string var2 = "The " + '\u0022' + "use" + '\u0022' + " of quotations causes difficulties.";

  • Another way of assigning this value to the variable without using quoted string is to define a constant for the quotation marks:

const string quotation_mark = "\"";

string var2 = "The " + quotation_mark + "use" + quotation_mark + " of quotations causes difficulties.";

Explanation:

In order to print and view the output of the above statements WriteLine() method of the Console class can be used.

   Console.WriteLine(var1);

   Console.WriteLine(var2);

In the first statement escape sequence \" is used in order to print: The "use" of quotations causes difficulties. This escape sequence is used to insert two quotation marks in the string like that used in the beginning and end of the word use.

In the second statement '\u0022' is used as an alternative to the quoted string which is the Unicode character used for a quotation mark.

In the third statement a constant named  quotation_mark is defined for quotation mark and is then used at each side of the use word to display it in double quotations in the output.

You might be interested in
Fryshta is using the Help window in PowerPoint to learn about inserting Smart Shapes into a presentation. She currently has a He
Rainbow [258]

Answer: Pin

Explanation:

Pin button is the button that is used for sticking or saving the ideas from the windows or web on that very place.This feature helps in reviewing or getting the idea back later anytime from the window as per users need. User use this button for saving any food recipe, steps of any process, guidelines etc.

  • According to the question, Fryshta can use pin button from the help window for sticking or pinning the steps of inserting shapes in her presentation.She can have a look at the steps whenever she want.
8 0
3 years ago
Can you help me with these AP Computer Science Questions. (THIS IS DUE BY 1:30 PM today) you have to evaluate the Boolean Expres
vfiekz [6]

Answer + Explanation:

'and' -> both statements are 'True' to evaluate as 'True'.

'or' -> at least one statement is 'True' to evaluate as 'True'.

1. True (grade has the value of 82, so the statement evaluates to 'True').

2. True (Both statements are true, this expression evaluates to 'True').

3. False (Both statements are false, this expression evaluates to 'False').

4. True (the != operator means <em>not equal.</em> Since the 'name' variable holds the string 'Rumpelstiltskin', name != 'Rumpelstiltskin' evaluates to 'False'. The 'not' operator returns the opposite of the given Boolean expression, so this expression evaluates to 'True').

5. True (name == 'Rumpelstiltskin' evaluates to 'True', so this expression is true).

6. False (All statements evaluate to 'False').

7. True (All statements evaluate to 'True').

8. False (All statements evaluate to 'True' except for <em>not(x == - 3) </em>which evaluates to 'False', so the whole statement now becomes false).

9. True (<em>grade+5 < 90 and grade >= 80 </em>evaluates to 'True', so this whole expression becomes true).

10. True (<em>grade > 0 and x % 2 == 1 </em>evaluates to 'True')

Hope this helps :)

7 0
3 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
Roses are red, violets are blue, I'm going to ki.ll myself, to make life better for you.
Shtirlitz [24]

Answer:

i like this poem helps out the world

Explanation:

p,s. deserves brainiest

6 0
3 years ago
Read 2 more answers
Volume of a cuboid is 14400 ​
Yanka [14]

Answer:

WHAT?

Explanation:

8 0
3 years ago
Other questions:
  • Categorize the following relationships into generalization, aggregation, or association. Beware, there may be n-ary associations
    14·1 answer
  • Off topic lol but does anyone know of a free app that lets you track family and friends like their location? Thx
    15·2 answers
  • A(n) __________ item is a hardware or software item that is to be modified and revised throughout its life cycle
    10·1 answer
  • BRAINLIEST !!A game design document is like a diary for game developers.
    11·1 answer
  • Which of the following is not a hazard a driver might encounter?
    5·1 answer
  • What does the binary odometer show about representing large numbers​
    15·1 answer
  • Which of the following can spreadsheet programs help a person with? (choose all that apply.)
    9·1 answer
  • What is the purpose of quick access toolbar?
    7·1 answer
  • if we try to use tail-recursive rules to implement non-tail-recursive rules, it will normally result in rules that are
    8·1 answer
  • When an event occurs, the agent logs details regarding the event. what is this event called?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!