1. The question about the weight of the football team players is statistical because it requires data collection to answer it and the data is variable.

2. The question about the height of Ben's mother is <u>non-statistical</u> because it does not require data collection to answer and the data is not variable, since it is one data point.

<h3>What is a statistical question?</h3>

A statistical question can be answered by collecting data and for which data will vary.

Questions answered with a single data point are <u>not statistical</u> because there is no data variability to answer them.

A statistical question can be determined by the following criteria:

Provides useful data about a group of people.
Many people can answer it.
There will be many different answers.
The data collected explains a situation or reality.

Thus, the question about the weight of the players asks a statistical question, unlike the height of Ben's mother.

Learn more about statistical questions at brainly.com/question/12150562

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4 0

2 years ago

Luis was worried about his Spanish final exam grade. The test had 200 questions, and he got

rodikova [14]

Answer:

Luis:

$\frac{175}{200} \times 100\% = 87.5\%$

Marina:

$\frac{130}{150} \times 100\% = 86.6\%$

Answer: Marina got the better percent score than Luis

Marina:

7 0

3 years ago

The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds

Bumek [7]

Answer: 11.5%

Explanation:

Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds.

Now, we get the z-score for 720 seconds by the following formula:

$\text{z-score} = \frac{x - \mu}{\sigma}$

where

$t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}$

So, the z-score of 720 seconds is given by:

$\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}$

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

$P(t \ \textgreater \ 720) 
\\ = P(z \ \textgreater \ 1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\ \boxed{P(t \ \textgreater \ 720) = 0.115}$

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice.

8 0

3 years ago

PLEASE HELP PLS!!!!!

Alisiya [41]

Subtitute f(x) with 2x + 1, and subtitute g(x) = -x + 4
f(x) = g(x)
2x + 1 = -x + 4

Then solve the equation above to find the value of x
Move the coefficient-variable x to the left side, and move the constants to the right side. When they are moved, addition becomes substraction, substraction becomes addition
2x + 1 = -x + 4
2x + x = 4 - 1

Simplify the equation
2x + x = 4 - 1
3x = 3

Move 3 on the left side to the right side, it becomes denominator
3x = 3
x = 3/3
x = 1

The solution to the equation is
x = 1

5 0

4 years ago

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