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const2013 [10]
3 years ago
9

The dimension of a rectangular pool are 24.5 feet by 13 feet. The depth of the water is 4 feet. Each cubic foot contains 7.48 ga

llons of water. How many gallons of water to the nearest tenth, are needed to fill the pool to 80% capacity
Mathematics
2 answers:
Vilka [71]3 years ago
8 0
Multiply length by width, and height. Than multiply the volume by 7.48 gal. Than you have the amount of water that can fill the whole pool. Than multiply by 0.8. and subtract it from the original volume. 
Contact [7]3 years ago
3 0

Answer:

Pool needed to be filled = 7623.62 gallons

Step-by-step explanation:

Length of rectangular pool = 24.5 feet

Width of rectangular pool = 13 feet

Depth of rectangular pool = 4 feet

Now, Volume of the pool = Length × Width × Depth

                                          = 24.5 × 13 × 4

                                          = 1274 cubic feet

Now, 1 cubic feet = 7.48 gallons

⇒ 1274 cubic feet = 7.48 × 1274

                              = 9529.52 gallons

So, Volume of the pool = 9529.52 gallons

Now, the pool is to be filled 80%

So, Pool needed to be filled = 9529.52 × 0.80

                                                 = 7623.62 gallons

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a box of crackers has a volume of 48 cubic inches. what is the volume of a similar box that is smaller by a scale factor of 2/3
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For this case what you need to know is that the original volume of the cookie box is:
 V = (w) * (l) * (h)
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 l: long
 h: height.
 We have then:
 V = (w) * (l) * (h) = 48 in ^ 3
 The volume of a similar box is:
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