Describe the graph that would be used to solve the equation –x2 + 4 = x + 2 using a system of equations. How will you use the gr
aph to find the solution(s)?
2 answers:
We want to solve
-x² + 4 = x + 2
Create two curves as follows:
y = -x² +4
and
y = x + 2
By graphing the two curves together, their points of intersection are the solutions.
y = -x² + 4 is a parabola with vertex at (0, 4), and it opens downward.
y = x + 2 is a straight line with slope - 1 and with y-intercept = 2
The points of intersection are (-2, 0) and (1, 3).
Answer:
The solutions are (-2, 0) and (1, 3).
-x² + 4 = x + 2
Create two curves as follows:
y = -x² +4
and
y = x + 2
By graphing the two curves together, their points of intersection are the solutions.
y = -x² + 4 is a parabola with vertex at (0, 4), and it opens downward.
y = x + 2 is a straight line with slope - 1 and with y-intercept = 2
The points of intersection are (-2, 0) and (1, 3).
Answer:
The solutions are (-2, 0) and (1, 3).
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If the length is three times the width and the area of the rectangle is
300 then the length of rectangle is 30m and width be 10m.
Given that the length is three times the width and the area of the rectangle is 300 .
We are required to find the length and breadth of the rectangle.
Area of the rectangle is basically the product of length and breadth.
let the breadth of rectangle be w.
The length of rectangle will be 3w.
Area=Length*Breadth
300=3w*w
300=3
100=
w=+10,-10 but ignore -10 because width cannot be negative.
Length=3w=3*10=30m
Width=w=10m
The area can be written as 3 because the area of rectangle is product of length and breadth.
Hence if the length is three times the width and the area of the rectangle is 300 then the length of rectangle is 30m and width be 10m.
Learn more about area at brainly.com/question/25292087
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