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vovangra [49]
3 years ago
14

An expression is shown below:

Mathematics
1 answer:
ladessa [460]3 years ago
6 0
4(m+3+5m)                           4(m+3+5m)
4(6m+3)                                4(6m+3)
 4x6m+12             or             4x3(2m+1)  
= 24m+12                               = 12(2m + 1 )
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Help!! whats the answer? and how do I solve!! :(
Sever21 [200]
I think the answer is 20.25 because when solving for the area of a triangle you do 1/2 base times height and so the equation would be
1/2(9)(4.5)
you would start by doing 9(4.5) which equals 40.5
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5 0
3 years ago
What is the area of a triangle that has a base of 10 inches and a height of 7 inches
Natali [406]

Answer:

it is 35

Step-by-step explanation:

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3 years ago
Simplify,<br> Rewrite the expression in the form 2n.<br> 2.2.2.2.2.2.2.2<br> 2.2.2.2
Nastasia [14]

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6 0
2 years ago
What is the area of the octagon?
Anna007 [38]

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Step-by-step explanation:

8 0
3 years ago
Isosceles JAM has convex angle M. JM=35,MA=4n+3, angle J=14w-1, and angle m=98 Find n. Find w. Find the perimeter of JAM
Lena [83]

Answer:

n = 8, w = 3 and perimeter = 122.83 units.

Step-by-step explanation:

Let the angle M is the angle between the equal sides of isosceles JAM.

So, JM = MA

⇒ 35 = 4n + 3

⇒ 4n = 32

⇒ n = 8 (Answer)

Now, if ∠ J = 14w - 1 and ∠ M = 98°, then

2(14w - 1) + 98 = 180

⇒ 2(14w - 1) = 82

⇒ 14w - 1 = 41

⇒ w = 3 (Answer)

Now, draw a perpendicular bisector on JA from vertex M and it meets JA at P say.

So, Δ MPJ will be a right triangle with ∠ J = (14w - 1) = 41° {Since w = 3}

Hence, \cos 41 = \frac{JP}{JM} = \frac{JP}{35}

⇒ JP = 35 cos 41 = 26.415

So, JA = 2 × JP = 52.83  

So, the perimeter of Δ JAM is = 35 × 2 + 52.83 = 122.83 units (Answer)

4 0
3 years ago
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