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Tatiana [17]
3 years ago
6

Solve the system of Linear equations by elimination

Mathematics
1 answer:
Delvig [45]3 years ago
3 0
With these, you pick either equation and a variable to solve for; let's solve for x using the 2nd eq: 3x - 4y = 11; 3x = 4y - 11; x = (4/3)y - (11/3).

Now, plug x into the first eq: 3( (4/3)y - (11/3) ) + 4y = 5; 4y -11 +4y = 5; 8y = 16; y = 2.

To get an actual number for x, plug in y into either equation and you should get x = -1.
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F(x) = x² + 6x+8<br> What is the vertex
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Answer:

(-3,-1)

Step-by-step explanation:

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The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K
GREYUIT [131]

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

M(2, 1) = (x_1, y_1)

P(12, 6) = (x_2, y_2)

m = 3, n = 2

Plug in the necessary values to find the coordinates of K:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{3(12) + 2(2)}{3 + 2}

x = \frac{36 + 4}{5}

x = \frac{40}{5}

x = 8

y = \frac{my_2 + ny_1}{m + n}

y = \frac{3(6) + 2(1)}{3 + 2}

y = \frac{18 + 2}{5}

y = \frac{20}{5}

y = 4

The coordinates of K = (8, 4)

3 0
3 years ago
Urgent! Two questions! (Pre Calc) (30 points)
mina [271]
Problem One
Sin(90 + q) = sin(90)*cos(q) + sin(q)*cos(90)
sin(90 + q) = 1 * cos(q) + sin(q)*0
sin(90 + q) = cos(q)

You can elimate anything beginning with Cos
You can also eliminate the sin function with a minus between it. 

Problem 2
Sin(x) = 1/csc(x) That makes C and D incorrect.
Correct answer has to be A. Since this is a multiple choice question you can't qualify the answer, but there are some points that exhibit questionable behavior, like 2 \pi *f*t = 0 for example. The function becomes undefined. 
4 0
3 years ago
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