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yarga [219]
2 years ago
8

Write the slope-intercept form of the equation for the line that passes through the point (-1,3) and has a slope of 5/3​

Mathematics
1 answer:
cricket20 [7]2 years ago
4 0

Answer:

y=\frac{5}{3}x+4\frac{2}{3}

Step-by-step explanation:

slope-intercept form: y = mx + b

Given:

Slope(m) = \frac{5}{3}

Point = (-1, 3)

To write the equation in slope-intercept form we need to know the slope(m) and the y-intercept(b). Since we already know the value of m, we can use it and the given point to find b:

3=\frac{5}{3}(-1)+b

3=-\frac{5}{3}+b

4\frac{2}{3}=b

Now that we know the values of b and m, we can write the equation:

y = \frac{5}{3}x+4\frac{2}{3}

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3 years ago
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ipn [44]

Answer:

a. [-3, 4]

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Step-by-step explanation:

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3 0
2 years ago
Find the m∡B to the nearest tenth of a degree if cos B = 0.8926 and ∡B is an acute angle
mrs_skeptik [129]

Answer:

26.8°

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If cos B = 0.8926

then arc cosine 0.8926  which may be expressed as cos-1 0.8926 will give the value of B.

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7 0
3 years ago
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Answer:

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Step-by-step explanation:


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