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yarga [219]
3 years ago
8

Write the slope-intercept form of the equation for the line that passes through the point (-1,3) and has a slope of 5/3​

Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

y=\frac{5}{3}x+4\frac{2}{3}

Step-by-step explanation:

slope-intercept form: y = mx + b

Given:

Slope(m) = \frac{5}{3}

Point = (-1, 3)

To write the equation in slope-intercept form we need to know the slope(m) and the y-intercept(b). Since we already know the value of m, we can use it and the given point to find b:

3=\frac{5}{3}(-1)+b

3=-\frac{5}{3}+b

4\frac{2}{3}=b

Now that we know the values of b and m, we can write the equation:

y = \frac{5}{3}x+4\frac{2}{3}

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Answer:

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Step-by-step explanation:

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Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

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<em>d = distance in ly (light-years) </em>

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Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

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3 years ago
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Archy [21]

It's been a while since I have done these kind of questions, but I would say a 180 transformation would be my best answer. Hope this helps a bit!

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