Answer:
Options (2) and (3)
Step-by-step explanation:
Let, 
-8 + 8i√3 = a² + b²i² + 2abi
-8 + 8i√3 = a² - b² + 2abi
By comparing both the sides of the equation,
a² - b² = -8 -------(1)
2ab = 8√3
ab = 4√3 ----------(2)
a = 
By substituting the value of a in equation (1),
48 - b⁴ = -8b²
b⁴ - 8b² - 48 = 0
b⁴ - 12b² + 4b² - 48 = 0
b²(b² - 12) + 4(b² - 12) = 0
(b² + 4)(b² - 12) = 0
b² + 4 = 0 ⇒ b = ±√-4
b = ± 2i
b² - 12 = 0 ⇒ b = ±2√3
Since, a =
For b = ±2i,
a = 
= 
= 
But a is real therefore, a ≠ ±2i√3.
For b = ±2√3
a = 
a = ±2
Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)
Options (2) and (3) are the correct options.
Answer and Step-by-step explanation:
The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.
Q's x and y are 1 , 1
R's x and y are 1 , 5
T's x and y are 5 , 1
S's x and y are 5 , 5
Now what you do is use the translation on all of these values.
Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)
R's x and y turns into -6 , 6
T's x and y are -2 , 2
S's x and y are -2 , 6
You can then plot the points on the graph and connect the lines to complete the reflection.
Hope this helps ! !
<3
The volume of one pan is 192 units cubed. The volume of the three pans is 576 units cubed.
Answer:
12/16 is greater than 0.12.
Step-by-step explanation:
0.12 = 12/100 = 6/50 = 3/25
12/16 = 3/4.
So, 12/16 is greater than 0.12.
A quadratic function is a function of the form
. The
vertex,
of a quadratic function is determined by the formula:
and
; where
is the
x-coordinate of the vertex and
is the
y-coordinate of the vertex. The value of
determines if the <span>
parabola opens upward or downward; if</span>
is positive, the parabola<span> opens upward and the vertex is the
minimum value, but if </span>
is negative <span>the graph opens downward and the vertex is the
maximum value. Since the quadratic function only has one vertex, it </span><span>could not contain both a minimum vertex and a maximum vertex at the same time.</span>
