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Sergio [31]
2 years ago
5

Please help a girl out

Mathematics
2 answers:
Trava [24]2 years ago
6 0

Answer:

r=\frac{7±3\sqrt{5} }{2}

Ignore the A before the ±. It wouldn't let me type it correctly.

Step-by-step explanation:

2r² + 7r - 1 = 3r²

2r² + 7r - 1 - 3r² = 0

- r² + 7r - 1 = 0

- (r² - 7r + 1) = 0

- (r² - 7r + 1) ÷ - 1 = 0 ÷ - 1

r² - 7r + 1 = 0

r=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

Ignore the A before the ±. It wouldn't let me type it correctly.

r² - 7r + 1 = 0

a = 1

b = - 7

c = 1

r=\frac{-(-7)±\sqrt{(-7)^{2}-4((1)(1)) } }{2(1)}

r=\frac{-(-7)±\sqrt{49-4((1)(1)) } }{2(1)}

r=\frac{-(-7)±\sqrt{49-4 } }{2(1)}

r=\frac{-(-7)±\sqrt{45 } }{2(1)}

r=\frac{-(-7)±\sqrt{(3)(3)(5) } }{2(1)}

r=\frac{7±(\sqrt{3 } )(\sqrt{3})(\sqrt{5})  }{2(1)}

r=\frac{7±3\sqrt{5} }{2}

Two separate equations

r=\frac{7+3\sqrt{5} }{2}

r=\frac{7-3\sqrt{5} }{2}

xxMikexx [17]2 years ago
3 0

Answer:

Quadratic formula is in the 2nd picture.

Step-by-step explanation:

Answers in the photo.

Solve the equation for r by finding a,b, and c  of the quadratic  then applying the quadratic formula.

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