Answer:
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
Step-by-step explanation:
Given



See attachment for spinner
Required
![P(Cube \ge 5\ and\ Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29)
On a number cube, we have:
---- i.e. 2 outcomes
So, the probability is:



On the spinner, we have:
---- i.e. 1 outcomes
So, the probability is:
![P(Spin[A]) = \frac{n(Spin[A])}{n(Spinner)}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7Bn%28Spin%5BA%5D%29%7D%7Bn%28Spinner%29%7D)
![P(Spin[A]) = \frac{1}{8}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B8%7D)
is calculated as thus:
![P(Cube \ge 5\ and\ Spin[A]) = P(Cube \ge 5) * P(Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20P%28Cube%20%5Cge%205%29%20%2A%20P%28Spin%5BA%5D%29)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{3} * \frac{1}{8}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%5Cfrac%7B1%7D%7B8%7D)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
First, x=1 is a vertical line. A line that is perpendicular would be horizontal so it would have a slope of 0. A line parallel to it would be vertical too so it would have and infinite gradient.
The answer is 600
25 x 4 =100
150 x 4 = 600
checking work
.25 x 600= 150
Answer:
MEDIAN: 3 IRQ (Interquartile Range): 2
Step-by-step explanation:
To find median, divide the number of data points by 2 (5/2) and round to the nearest whole. So, 5/2 = 2.5 rounded to nearest integer, is 3.
To find the interquartile range, subtract Q1 (1) from Q3 (3) which equals 2.
I hope dis right!!
Answer:
Step-by-step explanation:
The vertex is either the highest point on the parabola or the lowest point. We have a positive parabola, so the vertex is a low point. It sits at (2, -4). Locate that point and see what I mean by the lowest point on the parabola.