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3 years ago

10

Use the distributive property to create an equivalent expression to 9x+21

1 answer:

Romashka-Z-Leto [24]3 years ago

6 0

Answer:

9(x + 3)

Step-by-step explanation:

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What is the area of a regular heptagon with side length of 6 meters and a distance from the to the vertex of 6 meters? round you

Ahat [919]

Apothem = side length / 2*tan(180 / number of sides)
apothem = side length / 2*tan (180 / 7)
apothem = 6 / (2*tan( <span> <span> <span> 25.7142857143</span></span></span>))
apothem = 6 / 2*0.48157
<span><span><span>apothem = 6.2296239384 </span> </span> </span>

Polygon area = (# of sides * side length * apothem) / 2
Polygon area = ( 7 * 6 * <span>6.2296239384) / 2
</span><span><span><span>Polygon area = 130.8221027064 </span> </span> </span>

8 0

2 years ago

Let f(x) = 16 – x^2, g(x) = 4 – x. Find (fg)(x) and its domain.

pogonyaev

Answer:

x+4; all real numbers except =-4

Step-by-step explanation:

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

5 0

2 years ago

Simplify the expression to a polynomial in standard form:<br> (x+5)(2x² + 2x - 3)

Taya2010 [7]

Answer:

$\sf \: 2x {}^{3} + 12x {}^{3} + 7x - 15$

Step-by-step explanation:

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7 0

1 year ago

Read 2 more answers

The first step for deriving the quadratic formula from the quadratic equation, 0 = ax2 bx c, is shown.step 1: –c = ax2 bxwhich b

Ksju [112]

Answer:

option (b) is correct.

First step to solve for deriving the quadratic formula from the quadratic equation is completing the square.

Step-by-step explanation:

Given : the quadratic equation $ax^2+bx+c=0$

We have to find the first step for deriving the quadratic formula from the quadratic equation.

Quadratic formula is given by $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Consider the given quadratic equation $ax^2+bx+c=0$

Divide the equation by a, we get,

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

Take $\frac{c}{a}$ to other side, we get,

$x^2+\frac{b}{a}x=-\frac{c}{a}$

Add $(\frac{b}{2a})^2$ to both side, we get,

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}$

Thus, the left side is in the form of $(a+b)^2=a^2+b^2+2ab$

On solving, we get,

$(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}$

Then solve for x , we get quadratic formula $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Thus, first step to solve for deriving the quadratic formula from the quadratic equation is completing the square.

Thus, option (b) is correct.

3 0

2 years ago

Read 2 more answers

Help asap please i will give you a heart

atroni [7]

Answer:

32.4

Step-by-step explanation:

i knoiw it

8 0

2 years ago