<span>ds=<span>√<span>1+<span><span>(<span><span>dy</span><span>dx</span></span>)</span>2</span></span></span><span>dx</span>=<span>√<span>1+<span>14</span><span>(<span>x4</span>−2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span></span>
<span>=<span>√<span><span>14</span><span>(<span>x4</span>+2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span>=<span>√<span><span>1<span>22</span></span><span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span>2</span></span></span><span>dx</span></span>
<span>=<span>12</span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span><span>d<span>x</span></span></span>
Answer:
283
Step-by-step explanation:
130+17(9)
130 + 17 times the days
To solve this, you want to isolate h. Start by subtracting 9 from both sides: 16 = -3.2h. Divide by -3.2: h = -5
Answer:
To find the mean , median and mode of the students.
Step-by-step explanation:
The students choose from the three definitions of average to find the mean, median or mode of the students’ height in the school.
Students develop a strategy, collect and record data, and analyse data to answer this question.
The key concepts are
Consolidating the terms mean, median and mode.
The students should find the median of the height for the school if they have collected the median result of each grade.
Answer:
f(x) = 3x + 6.
Step-by-step explanation:
f(7) - f(0) = 27 - 6 = 21
so we may write a function:
f(x) = 3x + 6.
