Answer:
smallest number=626
middle number=628
larger number=630
Step-by-step explanation:
To find the numbers, let's use n as the variable. Since we know that the numbers are consecutive even numbers, we know that they increase by 2. For example, we could have 2+4+6=12.
Knowing that the consecutive numbers increase by two's, we can use this.
smallest number: n
middle number: n+2
larger number: n+4
All we have to do is add these together and set it equal to 1884.
n+(n+2)+(n+4)=1884 [combine like terms]
3n+6=1884 [subtract both sides by 6]
3n=1878 [divide both sides by 3]
n=626
Now that we know n=626, we also know that the other numbers are 626, 628, 630 respectively.
Answer:
14 2/3
Step-by-step explanation:
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Answer:
answer 11
Step-by-step explanation:
I think it the right answer
Answer:
Step-by-step explanation:
Since the length of time taken on the SAT for a group of students is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = length of time
u = mean time
s = standard deviation
From the information given,
u = 2.5 hours
s = 0.25 hours
We want to find the probability that the sample mean is between two hours and three hours.. It is expressed as
P(2 lesser than or equal to x lesser than or equal to 3)
For x = 2,
z = (2 - 2.5)/0.25 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
For x = 3,
z = (3 - 2.5)/0.25 = 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.97725
P(2 lesser than or equal to x lesser than or equal to 3)
= 0.97725 - 0.02275 = 0.9545
Answer:
21 matches
Step-by-step explanation:
This is a combination problem where we have to select two member out of 7 members
So we want calculation of 7C2
7C2 = 7!/[(2!)(7-2)!]
(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]
(7*6)/2 ~ Note everything that easily cancels here!
42/2
21 matches
