Part 1)
here we know that supply took 10 s to reach the ground
so here we will have
![y = \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![y = \frac{1}{2}\times 9.8 \times 10^2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%20%5Ctimes%2010%5E2)
![y = \frac{1}{2}\times 9.8 \times 100](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%20%5Ctimes%20100)
![y = 490 m](https://tex.z-dn.net/?f=y%20%3D%20490%20m)
Part 2)
Here all the supply covered horizontal distance of 650 m in 10 s interval of time
so here we can say
![speed = \frac{distance}{time}](https://tex.z-dn.net/?f=speed%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
![v = \frac{650}{10}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B650%7D%7B10%7D)
![v = 65 m/s](https://tex.z-dn.net/?f=v%20%3D%2065%20m%2Fs)
Answer:
(4) The particle travels with a constant velocity until t0 and then comes to rest.
Explanation:
Uniform rectilinear motion is defined as the motion of a particle in a straight line with constant velocity, that is, there is no change in velocity over time.
And this can be determined by means of the following equation:
![x=x_{o}+v*(t-t_{o})](https://tex.z-dn.net/?f=x%3Dx_%7Bo%7D%2Bv%2A%28t-t_%7Bo%7D%29)
where:
x = final point [m]
xo = initial point [m]
v = velocity (slope) [m/s]
t = final time [s]
to = initial time [s]
So the slope in the graph gives the constant velocity
![v=\frac{x-x_{o}}{t-t_{o}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx-x_%7Bo%7D%7D%7Bt-t_%7Bo%7D%7D)
Therefore, after the time to there is no displacement, that is the particle comes to rest.
Answer:
The Hubble telescope,which is taking detailed pictures of the universe.
Explanation:
Melting ice would damage this polar bears habitat meaning the polar bear may decrease
<span>95m /2 = 47.5m
47.5m = Vocos38t
</span><span>Vy = Voy -9.8t
0 = Vosin38 - 9.8t
0 = Vosin38 - 9.8(47.5 / Vocos38)
0 = Vo^2(0.62) - 590.7
</span>
<span>Vo = 30.87 m/s
</span>
Hope this helps