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lisabon 2012 [21]
3 years ago
5

Four penguins that are being playfully pulled along very slippery (frictionless) ice by a curator. The masses of three penguins

and the tension in two of the cords are 1 12 m kg = , 3 15 m kg = , 4 20 m kg = , 2 111TN= , 4 222TN= . Find the penguin mass 2m that is not given.
Physics
1 answer:
Sati [7]3 years ago
7 0

Answer:

m_2 = 23 kg

Explanation:

As we know that the tension in two strings are

T_2 = 111 N

T_4 = 222 N

now we have

F_{net} = ma

so we can say

(m_1 + m_2)a = T_2

(12 + m_2)a = 111

also we have

(m_1 + m_2 + m_3 + m_4) a = T_4

(12 + m_2 + 15 + 20) a = 222

now divide two equations

\frac{222}{111} = \frac{47 + m_2}{12 + m_2}

2m_2 + 24 = 47 + m_2

m_2 = 23 kg

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a transmission-line cable, of length 3 km, consists of 19 strands of identical copper conductors, each 1.5 mm in diameter. becau
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the resistance of the cable is 582.9 ohms

we are given the length of the cable which is  3 km,  of  1.5 mm in, the diameter  and resistivity of copper which is 1.72 m

The formula  we are referring to for calculating the resistance of the  cable is

R = ρl/A.

As there are 19 strands of copper conductors, so the resistance will be

R = 19( ρl/A)

Here  ρ is the resisitivity =  1.72 , l is the length  = 3(1+0.05)*10³3= 3150 m

A=pie/4(1.5 x 10⁻³)^2 =1.766 x 10⁻⁶ =1.766 x 10^-6

Substituting the values in the formula  we  get

R = 19 ( 1.72*3150 )/1.766 x 10⁻⁶

 = 582.9 ohm

To know more about resistance refer to the linkhttps://brainly.com/question/14547003?referrer=searchResults.

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1 year ago
1) A pendulum is configured to have a period of 2 seconds.
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Where are truss bridges located?
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A 0.540-kg bucket rests on a scale. Into this bucket you pour sand at the constant rate of 56.0 g/s. If the sand lands in the bu
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Answer:

a) 12.8212 N

b) 12.642 N

Explanation:

Mass of bucket = m = 0.54 kg

Rate of filling with sand  = 56.0 g/ sec = 0.056 kg/s

Speed of sand = 3.2 m/s

g= 9.8 m/sec2

<u>Condition (a);</u>

Mass of sand = Ms = 0.75 kg

So total mass becomes = bucket mass + sand mass = 0.54 +0.75=1.29 kg

== > total weight = 1.29 × 9.8 = 12.642 N

Now impact of sand = rate of filling × velocity = 0.056 × 3.2 =  0.1792 kg. m /sec2=0.1792 N

Scale reading is sum of impact of sand and weight force ;

i-e

scale reading = 12.642 N+0.1792 N = 12.8212 N

<u>Codition (b);</u>

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Competition in the Los Angeles Flower District results in
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Competition in the Los Angeles Flower District results in better quality flowers.

<h3>Why quality is the standard in flower competition?</h3>

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