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lisabon 2012 [21]
3 years ago
5

Four penguins that are being playfully pulled along very slippery (frictionless) ice by a curator. The masses of three penguins

and the tension in two of the cords are 1 12 m kg = , 3 15 m kg = , 4 20 m kg = , 2 111TN= , 4 222TN= . Find the penguin mass 2m that is not given.
Physics
1 answer:
Sati [7]3 years ago
7 0

Answer:

m_2 = 23 kg

Explanation:

As we know that the tension in two strings are

T_2 = 111 N

T_4 = 222 N

now we have

F_{net} = ma

so we can say

(m_1 + m_2)a = T_2

(12 + m_2)a = 111

also we have

(m_1 + m_2 + m_3 + m_4) a = T_4

(12 + m_2 + 15 + 20) a = 222

now divide two equations

\frac{222}{111} = \frac{47 + m_2}{12 + m_2}

2m_2 + 24 = 47 + m_2

m_2 = 23 kg

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Voltage-gated calcium ion channels open, and calcium ions diffuse into the cell

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A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric
Liula [17]

The electric field produced by a single-point charge is given by

E(r)=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge


To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.


1) The first charge is q=-3.00 nC=-3.00 \cdot 10^{-9} C, and it is located at x=0, so its distance from the point x=0.200 m is

r=0.200 m-0=0.2 m

Therefore, the electric field is

E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.


2) The second charge is q=-5.50 nC=-5.5 \cdot 10^{-9}C and it is located at x=0.800 m, so its distance from the point is

r=0.800 m-0.200 m=0.6 m

Therefore, the electric field is

E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.


3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C

and the sign tells us that the field is directed toward negative x-direction.

7 0
3 years ago
A block of aluminum measures 4.0 cm x 5.0 cm x 2.0 cm is completely immersed in a tank of water.
Aneli [31]

Answer:

upthrust or BUOYANT FORCE =Vdg

volume=LWH

upthrust=(4cm×5cm×2cm)×1g/cm²×g

upthrust=40cm³×1g/cm³×g

upthrust=40gf or 0.04kg×10m/s²=0.4N

weight of the displaced liquid is upthrust.

so mass=40g or 0.04kg

upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg

please mark brainliest, hope it helped

7 0
2 years ago
90cm uniform lever has a load 30N suspended at 15cm from one of it's end. If the fulcrum is at the center of gravity. The force
solniwko [45]

Answer: F = 20 N

Explanation:

I will ASSUME that the fulcrum is at the center of gravity of the lever arm, This means that the lever arm itself creates no moment about the fulcrum because there is no moment arm for that particular force.

To solve, we sum moments about any convenient point to zero (zero because there is no acceleration in the F = ma equation)

The easiest convenient point is the fulcrum

30((90/2) - 15) - F(90/2) = 0

           30(30) = F(45)

                    F = 900/45 = 20 N

3 0
2 years ago
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