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3 years ago

20 PTS BRAINLIEST If Thomson's model of the atom was correct, what would Rutherford have seen in his experiments?

Physics

2 answers:

12345 [234]3 years ago

8 0

Answer:

The correct answer is A

Explanation:

This is because in J.J. Thompson model, there would be no nucleus to reflect the alpha particles. This means there would be no reflection of the particles, making the answer A

Sati [7]3 years ago

5 0

The correct option is A.
J.J Thompson proposed the plum model of atomic structure. The model states that the atom is a sphere of positively charged matter in which electrons are embedded.
Rutherford designed an experiment to verify the truth of this model. He set up a beam of alpha particles which are to be passed a thin gold foil. If the JJ model of atomic structure is correct, all of the alpha particles suppose to pass through the foil, but some of the alpha particles bounced back while those that passed through the foil emerged at different angles.

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Answer:

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Explanation:

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If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.

Alexeev081 [22]

Answer:

$v=$

Explanation:

We are given that

Magnitude of vector v= $\mid v\mid =4$

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$\theta=\frac{\pi}{3}$

$v_x=\mid v\mid cos\theta$

$v_y=\mid v\mid sin\theta$

Substitute the values then we get

$v_x=4cos\frac{\pi}{3}$

$v_x=4\times \frac{1}{2}=2$

$cos\frac{\pi}{3}=\frac{1}{2}$

$v_y=4\times sin\frac{\pi}{3}=4\times \frac{\sqrt 3}{2}=2\sqrt 3$

$sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Therefore, the vector v in component form $=$

$v=$

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