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Evgen [1.6K]
3 years ago
14

Solving equtions in a row

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
4 0
1st: x = -5y - 5z - 2
2nd: x = 5y/4 - z + 19/4
3rd: x = -5y + z - 20
Not sure if this was correct, but anyways hope this helps! :)
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In a rhombus whose side measures 20 and the smaller angle is 38°. Find the length of the larger diagonal, to the nearest tenth.
Lemur [1.5K]

A rhombus diagonals form right angles. The diagonals also cut in half the angles

use cosine: cos38 = \frac{a}{20\\\\}

a = 20cos38

a=15.8

4 0
3 years ago
7) Original price: ?<br> Discount: 25%<br> Sale price:<br> $28
Studentka2010 [4]

Answer:

Step-by-step explanation:

let be x the price before the discount

original price= 28/(1-0.25)=28/0.75=37.33

original price=37.33

3 0
2 years ago
Read 2 more answers
What are the coordinates of the midpoint between the points (-4, -9) and (-8, -5)? Select the best answer from the choices provi
OLga [1]
B). (-6,-7)

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
8 0
2 years ago
Determine if the graph shows two quantities that vary directly. If possible, determine the constant of proportionality using the
tia_tia [17]

Answer:

Option C is correct option.

Step-by-step explanation:

We need to find k constant of proportionality

In the graph below let us take the values of x and y

x=150 , y=50

x=300, y=100

x=450, y=150

Now finding k using the formula: k=\frac{y}{x}

Putting values of x and y to find k

For x=150 , y=50 k = 50/150, k =1/3

For x=300, y=100 , k=100/300 , k=1/3

For x=450, y=150, k= 150/450 , k=1/3

Since for values of x and y, k = 1/3 is constant so, the graph shows two quantities that vary directly.

So, Option C is correct option.

5 0
3 years ago
A landscape contractor planted 37 tulip bulbs, 53 daffodil bulbs, and 82 crocus bulbs in each field. He planted bulbs in 174 fie
ohaa [14]
He planted D. 29,928 Bulbs
First Add up all the bulbs.
Then multiply the # of bulbs with the # of fields.
3 0
3 years ago
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