Answer:
H0: μ ≤ 1.30
H1: μ > 1.30
|Test statistic | > 1.833 ; Reject H0
Test statistic = 3.11
Yes
Pvalue = 0.006
Step-by-step explanation:
H0: μ ≤ 1.30
H1: μ > 1.30
Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54
Xbar = 14.84 / 10 = 1.484
Standard deviation, s = 0.187 (calculator)
Decison rule :
|Test statistic | > TCritical ; reject H0
df = n - 1 = 10 - 1 = 9
Tcritical(0.05; 9) = 1.833
|Test statistic | > 1.833 ; Reject H0
Test statistic :
(xbar - μ) ÷ (s/√(n))
(1.484 - 1.30) ÷ (0.187/√(10))
0.184 / 0.0591345
Test statistic = 3.11
Since ;
|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased
Pvalue estimate using the Pvalue calculator :
Pvalue = 0.006
3x-y=6, in order to be able to graph this you would have to change the equation to y=, so you need to subtract 3x from that side making it -y=-3x+6, now you need to y positive, so divide both sides by -1, thus making the equation look like y=3x-6, now if you can't plug this into a calculator to see what it would look like then you need to know what y=mx+b means. y is the equation you want to graph obviously, m = the slope, so our slope in this case would be -3, and b = our y intercept, so it would be (0,-6), so plot (0,-6) and use the slope to plot the rest of the points, some other points in this line should include (2,0), (-1,-9) and (4,6), just to name a few. Hope this helps.
Answer:
C
Step-by-step explanation:
Answer:
Step-by-step explanation:
GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.
TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.
SOLUTION:
Total number of different letters 
for two two-letter passwords 
different are required.
Number of ways of selecting different letters from 
letters
Hence there are different two-letter passwords can be formed using letters.
