Cos theta would be (adjacent side) / (hypotenuse), or 8/29.
Thus, the angle theta would be the inverse cosine of 8/29, which is
1.291 radians or 73.987 degrees.
Given this result, just take the sine of this angle.
Answer:
3x² + 3x - 36=
(3x+12)(x-3)
x² - 3x - 28=
(x+4)(x-7)
Step-by-step explanation:
For both equations use the method called the "Cross Method". It is useful for these type of factorisation questions called "Trinomials".
For more info on the cross method.
Here it is:
https://www.mathsteacher.com.au/year10/ch10_factorisation/05_cross_mult_method/cross.htm
Hope you enjoyed :D
I think your answer is c but I'm not sure
Answer:
anything :)))
Step-by-step explanation:
Answer:
If AB is a tangent to the circle, the triangle ABO is right angled, as the angle where a tangent meets the circumference is always 90 degrees.
We also know that Pythogoras' theorem only holds for right angled triangles.
The hypotenuse is 12 + 8 as 12 is the radius so is 20.
16^2+12^2 = 256 + 144 = 400 = 20^2 so AB must be tangent.
